[英]Programmatically open “View Source” HTML Window in Browser with Javascript?
我如何以編程方式打開“查看源代碼”窗口(使用某些Javascript),就像我在瀏覽器中右鍵單擊並單擊“查看源代碼”一樣? 這可能嗎?
您可以使用Firefox,Chrome和舊版IE支持的“視圖源” URI模式。
無需JavaScript,只需指向您希望用戶在源代碼視圖中看到的頁面的普通鏈接即可:
<a target="_blank" href="view-source:http://www.wikipedia.org/">view Wikipedia's home page HTML source</a>
更多信息:
您可以使用此腳本,我們只需獲取html標記的innerHTML,將其重新添加,然后將其粘貼到彈出窗口中即可。
function showSource(){;
var source = "<html>";
source += document.getElementsByTagName('html')[0].innerHTML;
source += "</html>";
//now we need to escape the html special chars, javascript has escape
//but this does not do what we want
source = source.replace(/</g, "<").replace(/>/g, ">");
//now we add <pre> tags to preserve whitespace
source = "<pre>"+source+"</pre>";
//now open the window and set the source as the content
sourceWindow = window.open('','Source of page','height=800,width=800,scrollbars=1,resizable=1');
sourceWindow.document.write(source);
sourceWindow.document.close(); //close the document for writing, not the window
//give source window focus
if(window.focus) sourceWindow.focus();
}
這不會完全顯示源代碼,因為它不會顯示HTML標記之外的任何內容,也不會顯示html標記內的任何屬性,但是它應該足夠靠近並且可以跨瀏覽器工作。
該解決方案相對於view-source的優勢在於:該解決方案也可以在Windows XP SP2的Internet Explorer 6>中使用。 如果您的受眾都不在這個組中,請使用view-source選項,該方法更簡單。
這將對支持view-source:
schema的view-source:
javascript:void(window.open('view-source:'+location.href))
可以從以下腳本中的鏈接創建一個書簽:
data:text/html;charset=utf-8,<html>
<a href="javascript:void(window.open('view-source:'+location.href))">view-source</a>
</html>
這樣的書簽可以在具有任意模式URI的任何頁面上使用,而不僅限於http:
或基於HTML
的頁面(因此沒有諸如.innerHTML
之類的屬性)。
因此,的URI(這些腳本適用於立即模式渲染):
data:image/png;base64,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
可以直接使用以下方法進行檢查:
view-source:data:image/png;base64,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
注意 :制作上述書簽是一個矛盾的過程,並且是多余的,因為通常,支持view-source:
schema(protocol)的瀏覽器直接在用戶界面中實現它-但是,某些界面嚴重受損,這就是為什么在使用時特別需要此書簽的原因:
window.navigator.userAgent=
Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.0.4) Gecko/2008102920 Firefox/3.0.4
(Splashtop-v1.2.17.0)
Device VM在Splashtop的“ Instant On”(即時)(非)環境中嚴重切斷了FF。
(提示:書簽
<a href="javascript:void(window.open('view-source:file:///'))">
use view-source to traverse and peruse Splashtop system files</a>
瀏覽Splashtop目錄結構,通常即: view-source:file://media/
)
魔鬼讓我這么做了-無法抗拒地闡述:
...此鏈接(sic
view-source:
:)可以在具有任意模式URI的任何頁面上使用...
包括自身,請觀察URI:
view-source:view-source:view-source:view-source:view-source:about:blank
產生明顯的HTML源,因此具有 .innerHTML
屬性
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html><head><title></title></head><body></body></html>
但
view-source:view-source:view-source:view-source:view-source:about:logo
不是HTML來源,因此沒有 .innerHTML
屬性。
至於
任意模式的URI:
view-source:jar:, view-source:chrome:, view-source:place:, ... ?
大概是這樣-只要瀏覽器可以使用具有特定架構的URI渲染頁面,則該頁面必須具有可解釋的源,該源可以被顯示,可查看,不包含解釋的呈現。
(即view-source:place:...
不會產生任何可行的頁面,但是place:...
URI都不會,盡管這樣的URI可以加書簽-至少使用FF [v。> 3.04?]
所以...
<a href='view-source:javascript:with(document){write(42);close();}' >v-s:js: answer</a>
<a href= 'javascript:with(document){write(42);close();}' >js: question</a>
根據您的使用情況,一種解決方案是將其作為Firefox附加組件或類似的附件來進行。
有2個選項[和解決方法,我將在后面解釋。
//get HTML from DOM (not really HTML from the server but an interrupted one - the plus is that it is immediate to fetch).
(function(){
"use strict";
var d = document.createElement("div");
d.style.cssText = "max-width:500px; max-height:200px; background-color:rgba(223,223,223,.7); border:3px solid rgba(0,0,0,.5); padding:5px; margin:10px; overflow-x:hidden; overflow-y:auto; word-break:break-word; font-family:'Courier New',Consolas,Lucida Console,monospace,sans-serif; text-shadow:.3px .3px rgba(0,0,0,.2),-0.3px -0.3px rgba(0,0,0,.2); border-radius:5px; box-shadow:1px 1px 5px rgba(0,0,0,.3),-1px -1px 5px rgba(0,0,0,.3)";
d.appendChild(document.createTextNode(document.querySelector('html').innerHTML));
document.querySelector('body').appendChild(d);
}());
這是“安全”的結果,沒有<html>
包裝和doctype
:
//get HTML from server, its the real-deal, but requires internet-connection (again...), since its the same-page you are OK to Ajax (domain wise..)
(function(){
var xhr = new XMLHttpRequest();
xhr.responseType = "text";
xhr.onreadystatechange = function(e){
var
xhr = e.target
, d = document.createElement("div")
;
if(xhr.DONE !== xhr.readyState) return;
d.style.cssText = "max-width:500px; max-height:200px; background-color:rgba(223,223,223,.7); border:3px solid rgba(0,0,0,.5); padding:5px; margin:10px; overflow-x:hidden; overflow-y:auto; word-break:break-word; font-family:'Courier New',Consolas,Lucida Console,monospace,sans-serif; text-shadow:.3px .3px rgba(0,0,0,.2),-0.3px -0.3px rgba(0,0,0,.2); border-radius:5px; box-shadow:1px 1px 5px rgba(0,0,0,.3),-1px -1px 5px rgba(0,0,0,.3)";
d.appendChild(document.createTextNode(xhr.responseText));
document.querySelector('body').appendChild(d);
}
xhr.open("GET", String(window.location.href), true);
xhr.send();
}());
這是並行結果,請注意區別。
筆記和東西..:
最簡單的方法是使用以下1行Java代碼:
//function showSource() {
window.location = "view-source:" + window.location;
//}
我希望它與您的瀏覽器兼容!
您可以執行以下操作,但它不是原始的HTML源:遍歷DOM並通過輸出找到的節點的屬性/值來重新創建源。
這不是一件容易的事(實際上是一項艱巨的任務),但這顯然是您唯一的選擇。
謝謝
PS。 我認為FF正在這樣做,因為在來源上總是存在細微的差異。
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