[英]Calculating percentage within a group
給出一個表格,用於以下命令:
select sex, count(*) from my_table group by sex;
select sex, employed, count(*) from my_table group by sex, employed;
得到:
sex | count
-------+------
male | 1960
female | 1801
和:
sex | employed | count
---------+----------+-------
male | f | 1523
male | t | 437
female | f | 1491
female | t | 310
我在編寫查詢時遇到困難,該查詢將計算每個性別組中的就業百分比。 所以輸出應該如下所示:
sex | employed | count | percent
---------+----------+--------+-----------
male | f | 1523 | 77.7% (1523/1960)
male | t | 437 | 22.3% (437/1960)
female | f | 1491 | 82.8% (1491/1801)
female | t | 310 | 17.2% (310/1801)
可能為時已晚,但對於即將到來的搜索者,可能的解決方案可能是:
select sex, employed, COUNT(*) / CAST( SUM(count(*)) over (partition by sex) as float)
from my_table
group by sex, employed
通過IO統計,這似乎是最有效的解決方案 - 可能取決於要查詢的行數 - 在上面的數字上測試...
同樣的態度可用於獲得男/女比例:
select sex, COUNT(*) / CAST( SUM(count(*)) over () as float)
from my_table
group by sex
此致,Jan
您可以使用子選擇和連接來執行此操作:
SELECT t1.sex, employed, count(*) AS `count`, count(*) / t2.total AS percent
FROM my_table AS t1
JOIN (
SELECT sex, count(*) AS total
FROM my_table
GROUP BY sex
) AS t2
ON t1.sex = t2.sex
GROUP BY t1.sex, employed;
我無法想到其他方法。
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