mysql查詢錯誤，嘗試連接表

Question

誰能看到為什么此代碼返回錯誤？

    "SELECT
a.widget_id,
c.additional_widget_id
FROM
exp_widgets AS a,
INNER JOIN exp_widget_additional AS c ON a.entry_id = c.additional_entry_id
WHERE
a.template = 3
AND
c.additional_template_id = 3
AND
(a.entry_id = 6 OR c.additional_entry_id = 6)
";

任何幫助表示贊賞。

Answer 1

您有一個流氓逗號：

...
exp_widgets AS a,
INNER JOIN exp_widget_additional`
...

應該

...
exp_widgets AS a
INNER JOIN exp_widget_additional
...