Django自定義SQL在查詢返回2時返回單行結果？

Question

我有一個自定義SQL調用，它向模板返回的結果與直接對數據庫運行相同查詢時得到的結果不同（1行vs 2）

查詢-從Django調試工具欄中復制：

SELECT  ((Sum(new_recruit_interviews) / Sum(opportunities_offered)) * 100) as avg_recruit, ((Sum(inspections) / Sum(presentations)) * 100) as avg_inspect, ((Sum(contracts_signed) / Sum(roof_approvals)) * 100) as avg_contracts, ((Sum(adjusters) / Sum(contracts_signed)) * 100) as avg_adjusters, ((Sum(roof_approvals) / Sum(adjusters)) *100) as roof_approval_avg, ((Sum(roof_turned_in) / Sum(adjusters)) * 100) as roof_jobs_avg, Sum(roof_turned_in) as roof_jobs_total,
((Sum(siding_approvals) / Sum(adjusters)) *100) as siding_approval_avg, ((Sum(siding_turned_in) / Sum(adjusters)) * 100) as siding_jobs_avg, Sum(siding_turned_in) as siding_jobs_total, ((Sum(gutter_approvals) / Sum(adjusters)) *100) as gutter_approval_avg, ((Sum(gutter_turned_in) / Sum(adjusters)) * 100) as gutter_jobs_avg, Sum(gutter_turned_in) as gutter_jobs_total,
((Sum(window_approvals) / Sum(adjusters)) *100) as window_approval_avg, ((Sum(window_turned_in) / Sum(adjusters)) * 100) as window_jobs_avg, Sum(window_turned_in) as window_jobs_total,
(Sum(roof_turned_in) + Sum(siding_turned_in) + Sum(gutter_turned_in) + Sum(window_turned_in)) as total_jobs,
(((Sum(collections_jobs_new) + Sum(collections_jobs_previous)) / (Sum(roof_turned_in) + Sum(siding_turned_in) + Sum(gutter_turned_in) + Sum(window_turned_in))) * 100) as total_collections,
sales_report_salesmen.location_id as detail_id, business_unit_location.title as title
FROM sales_report_salesmen
Inner Join auth_user ON sales_report_salesmen.user_id = auth_user.id
Inner Join business_unit_location ON sales_report_salesmen.location_id = business_unit_location.id
GROUP BY location_id

直接查詢運行上述查詢的結果：

INSERT INTO `` (`avg_recruit`, `avg_inspect`, `avg_contracts`, `avg_adjusters`, `roof_approval_avg`, `roof_jobs_avg`, `roof_jobs_total`, `siding_approval_avg`, `siding_jobs_avg`, `siding_jobs_total`, `gutter_approval_avg`, `gutter_jobs_avg`, `gutter_jobs_total`, `window_approval_avg`, `window_jobs_avg`, `window_jobs_total`, `total_jobs`, `total_collections`, `detail_id`, `title`)
   VALUES (95.3968, 92.8178, 106.9622, 90.2928, 103.5420, 103.5670, 4152, 100.2494, 106.8845, 4285, 120.1297, 86.2559, 3458, 92.9658, 106.1611, 4256, 16151, 4.281469, 12, 'St Paul, MN');

    VALUES (90.2982, 73.3723, 97.8474, 104.5433, 97.7585, 86.1848, 1884, 109.9268, 109.3321, 2390, 81.0156, 96.4318, 2108, 91.7200, 123.8792, 2708, 9090, 4.531573, 13, 'Denver, CO');

模板結果：

{'roof_jobs_total': Decimal('4152'), 'gutter_jobs_total': Decimal('3458'), 'avg_adjusters': Decimal('90.2928'), 'title': u'St Paul, MN', 'window_approval_avg': Decimal('92.9658'), 'total_collections': Decimal('4.281469'), 'gutter_approval_avg': Decimal('120.1297'), 'avg_recruit': Decimal('95.3968'), 'siding_approval_avg': Decimal('100.2494'), 'window_jobs_total': Decimal('4256'), 'detail_id': 12L, 'siding_jobs_avg': Decimal('106.8845'), 'avg_inspect': Decimal('92.8178'), 'roof_approval_avg': Decimal('103.5420'), 'roof_jobs_avg': Decimal('103.5670'), 'total_jobs': Decimal('16151'), 'window_jobs_avg': Decimal('106.1611'), 'avg_contracts': Decimal('106.9622'), 'gutter_jobs_avg': Decimal('86.2559'), 'siding_jobs_total': Decimal('4285')}

嘗試了幾種調整方式，並通過各種for循環運行結果，並獲得相同的結果，其中我的結果是通過Django模板的一行，而預期結果（通過控制台）有2行

返回的行與通過控制台查詢返回的第一行相同，因此我認為它正在正確運行，只是將結果傳遞給...。

從好的方面來說，這是我用來生成查詢的代碼（是的，這有點難看，一直在使用它）

def sql_grouped(table, fields, group_by=False, where=False):
from django.db import connection
query = 'SELECT %s FROM %s' % (fields, table)
if where:
     query = query + ' WHERE %s' % (where)
if group_by:
    query = query + ' GROUP BY %s' % (group_by)

cursor = connection.cursor()
cursor.execute(query)

desc = cursor.description
data = [dict(zip([col[0] for col in desc], row)) for row in cursor.fetchall()]
return data[0]

任何反饋都將不勝感激-因為我意識到我可以直接在SQL而不是后期處理中生成平均值，因此可以跳過一些步驟

Answer 1

已解決 -參見上面的評論