[英]How to print the address an ada access variable points to?
我想打印訪問變量(指針)的地址以進行調試。
type Node is private;
type Node_Ptr is access Node;
procedure foo(n: in out Node_Ptr) is
package Address_Node is new System.Address_To_Access_Conversions(Node);
use Address_Node;
begin
Put_Line("node at address " & System.Address_Image(To_Address(n)));
end foo;
Address_Image返回地址的字符串表示形式。
System.Address_To_Access_Conversions是一個在地址和訪問類型之間進行轉換的通用包(參見ARM 13.7.2 ),定義如下:
generic
type Object(<>) is limited private;
package System.Address_To_Access_Conversions is
-- [...]
type Object_Pointer is access all Object;
-- [...]
function To_Address(Value : Object_Pointer) return Address;
-- [...]
end System.Address_To_Access_Conversions;
gnat為上面定義的過程foo給出了以下錯誤:
expected type "System.Address_To_Access_Conversions.Object_Pointer" from instance at line... found type "Node_Ptr" defined at ...
Object_Pointer被定義為訪問所有Object。 根據我的理解,Object類型是Node,因此Object_Ptr訪問所有Node。 什么是gnat抱怨?
我想我對Ada泛型的理解是有缺陷的,我沒有正確使用System.Address_To_Access_Conversions。
編輯:我用“gnatmake -gnatG”編譯我的代碼來查看泛型實例化:
package address_node is
subtype btree__clear__address_node__object__2 is btree__node;
type btree__clear__address_node__object_pointer__2 is access
all btree__clear__address_node__object__2;
function to_address (value :
btree__clear__address_node__object_pointer__2) return
system__address;
end address_node;
btree__node是上面定義的Node類型的錯位名稱,所以我認為to_address()的參數類型是正確的,但是gnat正在抱怨(見上文)。
我現在面前沒有編譯器,但這不起作用嗎?
procedure foo(n: in out Node_Ptr) is
begin
Put_Line("node at address " & System.Address_Image(n.all'address)); --'
end foo;
好的,顯式類型轉換可以解決問題:
procedure Foo(n: in out Node_Ptr) is
package Address_Node is new System.Address_To_Access_Conversions(Node);
use Address_Node;
p : Address_Node.Object_Pointer;
begin
p := Address_Node.Object_Pointer(n);
Put_Line("node at address " & System.Address_Image(To_Address(p)));
end Foo;
需要一段時間習慣阿達... ;-)
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