從PHP頁面以Java下載多媒體內容

Question

網址： http : //www.teamliquid.net/replay/download.php? replay=1830是指向.rep文件的下載鏈接。

我的問題是：如何在Java中下載此內容（知道原始rep文件的名稱），以便使用已定義的前綴將其保存，例如path / _。rep

//我試圖從Java運行wget，但是我看不到如何獲取原始文件的名稱。

Answer 1

獲取重定向的URL，

http://www.teamliquid.net/replay/upload/coco%20vs%20snssoflsekd.rep

您可以從該URL獲取文件名。

獲取重定向的URL很棘手。 關於如何使用Apache HttpClient 4看到我對這個問題的回答，

HttpClient 4-如何捕獲最后一個重定向URL

編輯：這是使用HttpClient 4.0的示例，

String url = "http://www.teamliquid.net/replay/download.php?replay=1830";
HttpClient httpClient = new DefaultHttpClient();
HttpGet httpget = new HttpGet(url);
HttpContext context = new BasicHttpContext(); 
HttpResponse response = httpClient.execute(httpget, context); 
if (response.getStatusLine().getStatusCode() != HttpStatus.SC_OK)
    throw new IOException(response.getStatusLine().toString());
HttpUriRequest currentReq = (HttpUriRequest) context.getAttribute( 
    ExecutionContext.HTTP_REQUEST);
String currentUrl = URLDecoder.decode(currentReq.getURI().toString(), "UTF-8");
int i = currentUrl.lastIndexOf('/');
String fileName = null;
if (i < 0) {
    fileName = currentUrl;
} else {
    fileName = currentUrl.substring(i+1);
}
OutputStream os = new FileOutputStream("/tmp/" + fileName);
InputStream is = response.getEntity().getContent();
byte[] buf = new byte[4096];  
int read;  
while ((read = is.read(buf)) != -1) {  
   os.write(buf, 0, read);  
}  
os.close();

運行這段代碼后，我得到了這個文件，

/tmp/coco vs snssoflsekd.rep