[英]MySQLi Prepared Statement Query Issue
我對MySQLi准備的語句比較陌生,並且遇到錯誤。 采取以下代碼:
$user = 'admin';
$pass = 'admin';
if ($stmt = $mysqli->query("SELECT * FROM members WHERE username='$user' AND password='$pass'"))
{
echo $stmt->num_rows;
}
它將顯示為“ 1”。
下一段代碼雖然返回“ 0”:
$user = 'admin';
$pass = 'admin';
if ($stmt = $mysqli->prepare("SELECT * FROM members WHERE username=? AND password=?"))
{
$stmt->bind_param("ss", $user, $pass);
$stmt->execute();
echo $stmt->num_rows;
}
有什么想法嗎?
您需要在獲取行數之前調用store_result()
$user = 'admin';
$pass = 'admin';
if ($stmt = $mysqli->prepare("SELECT * FROM members WHERE username=? AND password=?")) { $stmt->bind_param("ss", $user, $pass); $stmt->execute(); $stmt->store_result(); // add this line echo $stmt->num_rows; }
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.