如何在Django中按日期對對象進行分組？

Question

我正在嘗試在articles表中選擇所有對象，並將它們按日期分組。 我認為它看起來類似於：

articles = Article.objects.filter(pub_date__lte=datetime.date.today()).group_by(pub_date.day)
articles = {'2010-01-01': (articleA, articleB, articleC...),
            '2010-01-02': (article1, article2, article3...)...}

Answer 1

這是ignacio建議使用itertools.groupby的一個可行示例。

class Article(object):
    def __init__(self, pub_date):
        self.pub_date = pub_date


if __name__ == '__main__':
    from datetime import date
    import itertools
    import operator

    # You'll use your Article query here instead:
    # a_list = Article.objects.filter(pub_date__lte = date.today())
    a_list = [
        Article(date(2010, 1, 2)),
        Article(date(2010, 2, 3)),
        Article(date(2010, 1, 2)),
        Article(date(2011, 3, 2)),
    ]


    keyfunc = operator.attrgetter('pub_date')

    a_list = sorted(a_list, key = keyfunc)
    group_list = [{ k.strftime('%Y-%m-%d') : list(g)} 
                  for k, g in itertools.groupby(a_list, keyfunc)]

    print group_list

輸出：

[{'2010-01-02': [<__main__.Article object at 0xb76c4fec>, <__main__.Article object at 0xb76c604c>]}, {'2010-02-03': [<__main__.Article object at 0xb76c602c>]}, {'2011-03-02': [<__main__.Article object at 0xb76c606c>]}]

Answer 2

itertools.groupby()

Answer 3

也許您應該在模板級別執行此操作？ 如果是這樣，您只需要這樣： 重新組合tempalte標簽