Erlang-根據值將列表分成多個列表

Question

我正在嘗試拆分此列表

List = [[<<"5">>, <<"54">>], [<<"00">>], [<<"35">>, <<"54">>, <<"45">>, <<"55">>], [<<"00">>],[ <<"5">>]]

成

List = [[<<"5">>, <<"54">>], [<<"35">>, <<"54">>, <<"45">>, <<"55">>], [<<"5">>]]

基本上基於<<“ 00” >>

最好的BIF解決方案是什么，我有一些代碼，但是它草率，我正在嘗試學習。

謝謝

編輯：

嘗試以下方法，不起作用

Done2 =列表：splitwith（[<<“ 00” >>]，Done1），

編輯：這行有效！

7> lists:splitwith(fun(A) -> A == [<<"00">>] end, List).
{[],
 [[<<"5">>,<<"54">>],
  [<<"00">>],
  [<<"35">>,<<"54">>,<<"45">>,<<"55">>],
  [<<"00">>],
  [<<"5">>]]}

但是，我需要一些更復雜的東西：比如當delim為[<<“ 00” >>，<<“ 23” >>]時

9> List = [[<<"5">>,<<"54">>], [<<"00">>,<<"23">>], [<<"35">>,<<"54">>], [<<"5">
>], [<<"00">>, <<"23">>]].

[[<<"5">>,<<"54">>],
 [<<"00">>,<<"23">>],
 [<<"35">>,<<"54">>],
 [<<"5">>],
 [<<"00">>,<<"23">>]]

10> lists:splitwith(fun(A) -> A == [<<"00">>] end, List).
{[],
 [[<<"5">>,<<"54">>],
  [<<"00">>,<<"23">>],
  [<<"35">>,<<"54">>],
  [<<"5">>],
  [<<"00">>,<<"23">>]]}

11> lists:splitwith(fun(A) -> A == [<<"00">>,<<"23">>] end, List).
{[],
 [[<<"5">>,<<"54">>],
  [<<"00">>,<<"23">>],
  [<<"35">>,<<"54">>],
  [<<"5">>],
  [<<"00">>,<<"23">>]]}
12>

那里沒有運氣

Answer 1

我不確定我是否正確理解您的要求。 這是一個可能的解決方案。 它將在[[<<“ 00” >> | _]。

1> List = [[<<"5">>, <<"54">>], [<<"00">>], [<<"35">>, <<"54">>, <<"45">>, <<"55">>], [<<"00">>, <<"23">> ],[ <<"5">>]].
[[<<"5">>,<<"54">>],
 [<<"00">>],
 [<<"35">>,<<"54">>,<<"45">>,<<"55">>],
 [<<"00">>,<<"23">>],
 [<<"5">>]]
2> List2 =  [ X || X <- List, case X of [ <<"00">> | _ ] -> false; _ -> true end].                                      
[[<<"5">>,<<"54">>],
 [<<"35">>,<<"54">>,<<"45">>,<<"55">>],
 [<<"5">>]]

Answer 2

1>列表= [[<<“ 5” >>，<<“ 54” >>]，[<<“ 00” >>，<<“ 23” >>]，[<<“ 35” >>， <<“ 54” >>]，[<<“ 5” >>]，[<<“ 00” >>，<<“ 23” >>]]]。 [[<<“ 5” >>，<<“ 54” >>]，[<<“ 00” >>，<<“ 23” >>]，[<<“ 35” >>，<<“ 54 “ >>]，[<<” 5“ >>]，[<<” 00“ >>，<<” 23“ >>]]]

2>分隔符= [<<“ 00” >>，<<“ 23” >>]。
[<< “00” >>，<< “23” >>]

3> list：filter（fun（L）-> L / =分隔符結尾，列表）。
[[<< “5” >>，<< “54” >>]，[<< “35” >>，<< “54” >>]，[<< “5” >>]]