[英]How to Take Part of a String using One of the T-SQL Text Functions
我有以下片段:
CONVERT(varchar, FLOOR(ROUND((DATEDIFF(minute, shiftStart.timeEntered, shiftEnd.timeEntered) - DATEDIFF(minute,
lunchStart.timeEntered, lunchEnd.timeEntered)) * 1.0 / 60, 2, 1))) + ':' + CONVERT(varchar, ROUND(ROUND(DATEDIFF(minute, shiftStart.timeEntered,
shiftEnd.timeEntered) * 1.0 / 60, 2, 1) % 1 * 60, 0)) AS WorkingHours
上面的代碼以以下格式打印小時和分鍾:
4:30.000000
7:40.000000
8:1.000000
我需要擺脫。 和下一個0,所以我得到以下格式:
4:30 (4 hours and 30 mins)
7:40 (7 hours and 40 minutes)
8:1 (means 8 hours and 1 minute)
.0000無害,但外觀不好
將分鍾部分轉換為INTeger,然后再轉換為VARCHAR以刪除十進制值:
CONVERT(VARCHAR,
CONVERT(INT, ROUND(ROUND(DATEDIFF(minute, shiftStart.timeEntered, shiftEnd.timeEntered) * 1.0 / 60, 2, 1) % 1 * 60, 0)))
完整示例:
CONVERT(varchar, FLOOR(ROUND((DATEDIFF(minute, shiftStart.timeEntered, shiftEnd.timeEntered) - DATEDIFF(minute, lunchStart.timeEntered, lunchEnd.timeEntered)) * 1.0 / 60, 2, 1))) + ':' +
CONVERT(VARCHAR, CONVERT(INT, ROUND(ROUND(DATEDIFF(minute, shiftStart.timeEntered, shiftEnd.timeEntered) * 1.0 / 60, 2, 1) % 1 * 60, 0))) AS WorkingHours
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