[英]Java while loops/ math logic
我是Java的新手,也是while,for和if / else語句的新手。 我真的一直在與這個問題的野獸掙扎。
代碼和說明如下。 它編譯,但我沒有按預期計算。 我不確定這是一個數學邏輯錯誤,循環布局錯誤,還是兩者兼而有之。
我一直在研磨我的齒輪已經有一段時間了,而且我無法看到它。 我覺得我真的很親密......但還是那么遙遠。
碼:
/*
This program uses a while loop to to request two numbers and output (inclusively) the odd numbers between them,
the sum of the even numbers between them, the numbers and their squares between 1 & 10, the sum of the squares
of odd numbers.
*/
import java.io.*;
import java.util.*;
public class SumOfaSquare
{
static Scanner console = new Scanner(System.in);
public static void main (String[] args)
{
int firstnum = 0, secondnum = 0, tempnum = 0;
int sum = 0,squaresum = 0, squarenum = 0;
int number = 1;
String oddOutputMessage = "The odd numbers between" + firstnum + " and " + secondnum + " inclusively are:";
String evenSumMessage = "The sum of all even numbers between " + firstnum + " and " + secondnum + "is: ";
String oddSquareMessage = "The odd numbers and their squares are : ";
String squareMessage = "The numbers and their squares from 1-10 are : ";
System.out.println ("Please enter 2 integers. The first number should be greater than the second: ");
firstnum = console.nextInt();
secondnum = console.nextInt();
//used to find out if first number is greater than the second. If not, inform user of error.
if (firstnum > secondnum)
{
tempnum = firstnum;
System.out.println ("You entered: " + firstnum + " and: " + secondnum);
}
else
System.out.println ("Your first number was not greater than your second number. Please try again.");
//while the frist number is greater, do this....
while (tempnum <= secondnum)
{
//if it's odd....
if (tempnum %2 == 1)
{
oddOutputMessage = (oddOutputMessage + tempnum + " ");
squaresum = (squaresum + tempnum * tempnum);
}
//otherwise it's even..
else
{
sum = sum + tempnum;
evenSumMessage = (evenSumMessage + sum + " ");
tempnum++;
}
}
// figures squares from 1 - 10
while (number <=10)
{
squarenum = (squarenum + number * number);
squareMessage = (squareMessage + number + " " + squarenum);
number++;
}
oddSquareMessage = oddSquareMessage + squaresum;
System.out.println (oddOutputMessage);
System.out.println (oddOutputMessage);
System.out.println (squareMessage);
System.out.println (evenSumMessage);
System.out.println (oddSquareMessage);
}
}
在第一個循環中,仔細考慮增加tempnum
的條件。 什么時候發生奇怪的事情? tempnum
會增加嗎?
您的代碼存在許多問題。 我寧願你自己解決這個問題。 如果您不知道如何調試代碼,可以使用“println”調試來打印出變量。
取輸入3和1並逐行瀏覽您的程序,並考慮答案將在您的頭腦中(或在紙上)。 看看它是否符合您的預期結果。
以下是有關您的代碼的一般注釋:
dumpOddNumbers(low, high), sumEvenNumbers(low, high), ...
for
循環。 該代碼的一個問題是,如果第一個數字<然后是第二個(例如輸入110),程序將永遠循環,因為如果數字是奇數,則tempnum不會遞增。 while (tempnum <= secondnum)
應該是for (int tempnum = firstnum; tempnum <= secondnum; tempnum++)
while (number <= 10)
應for (int number = 1; number <= 10; number++)
println(msgString + resultValue)
。 StringBuilder()
而不是msg = msg + ...
邏輯類型。 效率更高。 return
那里。 以下代碼與評論不符。 哪個是對的?
// while the frist number is greater, do this while (tempnum <= secondnum) {
希望這可以幫助。
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