[英]Need some help in creating a procedure
我需要一些幫助。
我的桌子是
CREATE TABLE `users` (
`id` bigint(11) NOT NULL auto_increment,
`point` bigint(11) NOT NULL,
`lefth` bigint(11) NOT NULL,
`righth` bigint(11) NOT NULL,
`referel` bigint(11) NOT NULL,
`dateadded` timestamp NOT NULL default CURRENT_TIMESTAMP,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci AUTO_INCREMENT=21 ;
數據
INSERT INTO `users` VALUES (1, 1000, 2, 4, 1, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (2, 0, 3, 5, 1, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (3, 0, 6, 9, 1, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (4, 0, 14, 7, 1, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (5, 0, 8, 0, 2, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (6, 0, 0, 0, 3, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (7, 0, 15, 19, 4, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (8, 0, 10, 11, 5, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (9, 0, 0, 0, 3, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (10, 0, 0, 0, 8, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (11, 0, 12, 13, 8, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (12, 0, 0, 0, 11, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (13, 0, 0, 0, 11, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (14, 0, 16, 17, 4, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (15, 0, 0, 0, 7, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (16, 0, 0, 0, 4, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (17, 0, 0, 18, 14, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (18, 0, 0, 0, 17, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (19, 0, 20, 0, 7, '0000-00-00 00:00:00');
INSERT INTO `users` VALUES (20, 0, 0, 0, 19, '0000-00-00 00:00:00');
我想編寫一個過程,當提供一個值作為參數時,將返回表中傳遞的參數下的所有值。
像這樣的東西
DELIMITER $$
--
CREATE DEFINER=`root`@`localhost` PROCEDURE `emp_heir`(
IN param1 INTEGER(11)
)
BEGIN
select lefth from users where id = param1;
END$$
這將僅返回lefth列中的值,但是如果lefth中的值具有子值(該id的lefth和righth中的值),則它也應返回該值。 就像明智的做法一樣,它應該持續到表格末尾。
如何做到這一點?
謝謝
CREATE DEFINER=`root`@`localhost` PROCEDURE `emp_heir` (IN param1 INTEGER(11), INOUT lResult VARCHAR(255), INOUT rResult VARCHAR(255))
BEGIN
DECLARE lh INT(11);
DECLARE rh INT(11);
IF lResult IS NULL THEN
SET lResult := '';
END IF;
IF rResult IS NULL THEN
SET rResult := '';
END IF;
SELECT lefth, righth FROM users where id = param1 INTO lh, rh;
IF lh != 0 THEN
SET lResult := CONCAT(lResult, lh, ',');
END IF;
IF rh != 0 THEN
SET rResult := CONCAT(rResult, rh, ',');
END IF;
IF lh != 0 THEN
CALL emp_heir(lh, lResult, rResult);
END IF;
IF rh != 0 THEN
CALL emp_heir(rh, lResult, rResult);
END IF;
END$$
檢查一下。 去測試:
call emp_heir(2, @lresult, @rresult, 0);
select @lresult, @rresult;
只是很有趣,為什么不在應用程序中執行此操作? =)
UPD
如果對此出錯,請執行
SET max_sp_recursion_depth = 10;
如果錯誤再次出現,請嘗試增加該值
這就是你想要的嗎?
DELIMITER $$
CREATE PROCEDURE my(
IN number INT,
OUT lefte INT,
OUT righte INT
)
BEGIN
SELECT lefth, righth
FROM users WHERE id = number INTO lefte , righte;
END;
$$
DELIMITER ;
電話就像:
CALL my(4,@lefth,@righth);
SELECT @lefth,@righth;
CREATE DEFINER=`root`@`localhost` PROCEDURE `emp_heir` (IN param1 INTEGER(11))
BEGIN
DECLARE lh INT(11);
DECLARE rh INT(11);
DECLARE lresult VARCHAR(255) default '';
DECLARE rresult VARCHAR(255) default '';
SET lh := param1;
SET rh := param1;
REPEAT
SELECT lefth FROM users WHERE id = lh INTO lh;
SET lresult := CONCAT(lresult, lh, ',');
UNTIL lh = 0 END REPEAT;
REPEAT
SELECT righth FROM users WHERE id = rh INTO rh;
SET rresult := CONCAT(rresult, rh, ',');
UNTIL rh = 0 END REPEAT;
SELECT LEFT(lresult, LENGTH(lresult) - 3) AS lefths, LEFT(rresult, LENGTH(rresult) - 3) AS righths;
END$$
你有沒有這樣的意思? 此過程以遞歸方式獲取所有lefth
和righth
值,並將其放入單獨的字符串中。
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