[英]How to generate a human readable time range using ruby on rails
我正在嘗試找到生成以下輸出的最佳方法
<name> job took 30 seconds
<name> job took 1 minute and 20 seconds
<name> job took 30 minutes and 1 second
<name> job took 3 hours and 2 minutes
我開始這段代碼
def time_range_details
time = (self.created_at..self.updated_at).count
sync_time = case time
when 0..60 then "#{time} secs"
else "#{time/60} minunte(s) and #{time-min*60} seconds"
end
end
有沒有更有效的方法可以做到這一點? 對於一些超級簡單的東西,似乎有很多冗余代碼。
另一個用途是:
<title> was posted 20 seconds ago
<title> was posted 2 hours ago
與此類似的代碼,但是我使用Time.now:
def time_since_posted
time = (self.created_at..Time.now).count
...
...
end
如果您需要比distance_of_time_in_words
更“精確”的東西,可以按照以下方式編寫:
def humanize secs
[[60, :seconds], [60, :minutes], [24, :hours], [Float::INFINITY, :days]].map{ |count, name|
if secs > 0
secs, n = secs.divmod(count)
"#{n.to_i} #{name}" unless n.to_i==0
end
}.compact.reverse.join(' ')
end
p humanize 1234
#=>"20 minutes 34 seconds"
p humanize 12345
#=>"3 hours 25 minutes 45 seconds"
p humanize 123456
#=>"1 days 10 hours 17 minutes 36 seconds"
p humanize(Time.now - Time.local(2010,11,5))
#=>"4 days 18 hours 24 minutes 7 seconds"
哦,關於您的代碼的一句話:
(self.created_at..self.updated_at).count
獲得差異的方法真的很糟糕。 簡單使用:
self.updated_at - self.created_at
DateHelper
中有兩種方法可以為您提供所需的信息:
time_ago_in_words( 1234.seconds.from_now ) #=> "21 minutes" time_ago_in_words( 12345.seconds.ago ) #=> "about 3 hours"
distance_of_time_in_words( Time.now, 1234.seconds.from_now ) #=> "21 minutes" distance_of_time_in_words( Time.now, 12345.seconds.ago ) #=> "about 3 hours"
chronic_duration將數字時間解析為可讀的,反之亦然
如果您想在幾秒到幾天的范圍內顯示重要的持續時間,則可以選擇(因為它不必表現最佳):
def human_duration(secs, significant_only = true)
n = secs.round
parts = [60, 60, 24, 0].map{|d| next n if d.zero?; n, r = n.divmod d; r}.
reverse.zip(%w(d h m s)).drop_while{|n, u| n.zero? }
if significant_only
parts = parts[0..1] # no rounding, sorry
parts << '0' if parts.empty?
end
parts.flatten.join
end
start = Time.now
# perform job
puts "Elapsed time: #{human_duration(Time.now - start)}"
human_duration(0.3) == '0'
human_duration(0.5) == '1s'
human_duration(60) == '1m0s'
human_duration(4200) == '1h10m'
human_duration(3600*24) == '1d0h'
human_duration(3600*24 + 3*60*60) == '1d3h'
human_duration(3600*24 + 3*60*60 + 59*60) == '1d3h' # simple code, doesn't round
human_duration(3600*24 + 3*60*60 + 59*60, false) == '1d3h59m0s'
另外,您可能只想在無關緊要的時候刪除秒部分(還演示了另一種方法):
def human_duration(duration_in_seconds)
n = duration_in_seconds.round
parts = []
[60, 60, 24].each{|d| n, r = n.divmod d; parts << r; break if n.zero?}
parts << n unless n.zero?
pairs = parts.reverse.zip(%w(d h m s)[-parts.size..-1])
pairs.pop if pairs.size > 2 # do not report seconds when irrelevant
pairs.flatten.join
end
希望能有所幫助。
distance_of_time_in_words
存在問題,如果您經過那里1小時30分鍾,它將返回大約2小時
只需添加助手:
PERIODS = {
'day' => 86400,
'hour' => 3600,
'minute' => 60
}
def formatted_time(total)
return 'now' if total.zero?
PERIODS.map do |name, span|
next if span > total
amount, total = total.divmod(span)
pluralize(amount, name)
end.compact.to_sentence
end
基本上只需幾秒鍾即可傳遞您的數據。
Rails有一個DateHelper
用於查看。 如果這不是您想要的,那么您可能必須編寫自己的。
@MladenJablanović有一個很好的示例代碼答案。 但是,如果您不介意繼續自定義示例人性化方法,那么這可能是一個很好的起點。
def humanized_array_secs(sec)
[[60, 'minutes '], [60, 'hours '], [24, 'days ']].inject([[sec, 'seconds']]) do |ary, (count, next_name)|
div, prev_name = ary.pop
quot, remain = div.divmod(count)
ary.push([remain, prev_name])
ary.push([quot, next_name])
ary
end.reverse
end
這為您提供了可以操縱的值和單位名稱的數組。
如果第一個元素不為零,則為天數。 您可能需要編寫代碼來處理多天,例如顯示幾周,幾個月和幾年。 否則,修剪掉前0
值,然后取下兩個。
def humanized_secs(sec)
return 'now' if 1 > sec
humanized_array = humanized_array_secs(sec.to_i)
days = humanized_array[-1][0]
case
when 366 <= days
"#{days / 365} years"
when 31 <= days
"#{days / 31} months"
when 7 <= days
"#{days / 7} weeks"
else
while humanized_array.any? && (0 == humanized_array[-1][0])
humanized_array.pop
end
humanized_array.reverse[0..1].flatten.join
end
end
該代碼甚至可以用於ruby while
語句。
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