[英]How to show records in a different order
我從這個小的PHP和mysql腳本開始。 我如何通過taskupdated列顯示任務?
$query = "SELECT * FROM tasks2 where owner=72";
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
echo $row['ownername'];
echo ' - ';
echo $row['tasktitle'];
echo '<br/>';
echo $row['taskdetails'];
echo '<hr/>';
}
<?php
$query = "SELECT * FROM tasks2 WHERE owner=72 ORDER BY taskupdated";
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
echo $row['ownername'];
echo ' - ';
echo $row['tasktitle'];
echo '<br />';
echo $row['taskdetails'];
echo '<hr />';
}
?>
如果要以其他方式對它們進行排序,請改用ORDER BY taskupdated DESC
。
SELECT * FROM tasks2 where owner=72 ORDER BY taskupdated
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