[英]CoreText drawing, receiving touches, touch coordinates messed up
我有一個使用coretext繪制一些文本的視圖。 一切正常,文字正面朝上,翻轉坐標。 但是,我還必須回應特定運行的觸摸,所以我有以下代碼,當點擊手勢識別器觸發時調用:
- (void)receivedTap:(UITapGestureRecognizer*)recognizer
{
CGPoint point = [recognizer locationInView:self];
NSLog(@"point = %@", NSStringFromCGPoint(point));
CGContextRef context = UIGraphicsGetCurrentContext();
CFArrayRef lines = CTFrameGetLines(textFrame);
CFIndex lineCount = CFArrayGetCount(lines);
CGPoint origins[lineCount];
CTFrameGetLineOrigins(textFrame, CFRangeMake(0, 0), origins);
for(CFIndex idx = 0; idx < lineCount; idx++)
{
CTLineRef line = CFArrayGetValueAtIndex(lines, idx);
CGRect lineBounds = CTLineGetImageBounds(line, context);
lineBounds.origin.y += origins[idx].y;
if(CGRectContainsPoint(lineBounds, point))
{
CFArrayRef runs = CTLineGetGlyphRuns(line);
for(CFIndex j = 0; j < CFArrayGetCount(runs); j++)
{
CTRunRef run = CFArrayGetValueAtIndex(runs, j);
NSDictionary* attributes = (NSDictionary*)CTRunGetAttributes(run);
BOOL result = NO;
NSURL* url = [attributes objectForKey:kJTextViewDataDetectorLinkKey];
NSString* phoneNumber = [attributes objectForKey:kJTextViewDataDetectorPhoneNumberKey];
NSDictionary* addressComponents = [attributes objectForKey:kJTextViewDataDetectorPhoneNumberKey];
if(url)
{
result = [[UIApplication sharedApplication] openURL:url];
return;
}
else if(phoneNumber)
{
NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"tel://%@", phoneNumber]];
result = [[UIApplication sharedApplication] openURL:url];
return;
}
else if(addressComponents)
{
NSMutableString* address = [NSMutableString string];
NSString* temp = nil;
if((temp = [addressComponents objectForKey:NSTextCheckingStreetKey]))
[address appendString:temp];
if((temp = [addressComponents objectForKey:NSTextCheckingCityKey]))
[address appendString:[NSString stringWithFormat:@"%@%@", ([address length] > 0) ? @", " : @"", temp]];
if((temp = [addressComponents objectForKey:NSTextCheckingStateKey]))
[address appendString:[NSString stringWithFormat:@"%@%@", ([address length] > 0) ? @", " : @"", temp]];
if((temp = [addressComponents objectForKey:NSTextCheckingZIPKey]))
[address appendString:[NSString stringWithFormat:@" %@", temp]];
if((temp = [addressComponents objectForKey:NSTextCheckingCountryKey]))
[address appendString:[NSString stringWithFormat:@"%@%@", ([address length] > 0) ? @", " : @"", temp]];
NSString* urlString = [NSString stringWithFormat:@"http://maps.google.com/maps?q=%@", [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
result = [[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlString]];
return;
}
}
}
}
}
這適用於第一行,例如,我正在進行一些數據檢測的網址。 我輕拍它,Mobile Safari就像我期望的那樣啟動。 但是,這僅在項目位於第一行時才有效。 我在其他行上看到文字的顏色和下划線(用於地址和電話號碼等內容),我已經驗證了相應的數據附加到字符串中的自定義屬性,但是當我點擊它們時,什么也沒發生。
我知道我必須以某種方式翻轉rect lineBounds
,但我不知道如何去做。 任何幫助將不勝感激。
實際上你需要做的是反過來迭代lines
。 例如,嘗試在此代碼中替換:
NSArray* tempLines = (NSArray*)CTFrameGetLines(textFrame);
CFIndex lineCount = [tempLines count];//CFArrayGetCount(lines);
NSMutableArray* lines = [NSMutableArray arrayWithCapacity:lineCount];
for(id elem in [tempLines reverseObjectEnumerator])
[lines addObject:elem];
CGPoint origins[lineCount];
反轉線條的最簡單方法
CFArrayRef lines = (CFArrayRef)[[(NSArray *)CTFrameGetLines(frame) reverseObjectEnumerator] allObjects];
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