[英]Toggle table row visibility based on presence of td class
如果<td>
類設置為特定類,如何在表中切換多行。 例如,如果它們包含class="foo"
則切換所有行。
<table id="bar">
<tr>
<td>hello</td>
<td class="foo">there</td>
<td class="foo">bye</td>
</tr>
</table>
這是一個非jQuery解決方案,專為您編寫: http : //phrogz.net/tmp/toggling_rows_with_class.html
這是相關的JS:
window.onload = function() {
var visible = true;
document.getElementById('toggle').onclick = function() {
visible = !visible;
var tds = findElementsWithClass('td', 'foo');
for (var i=0, len=tds.length; i<len; ++i) {
tds[i].parentNode.style.display = visible ? '' : 'none';
}
};
}
function findElementsWithClass(tagName, className) {
if (document.querySelectorAll) {
return document.querySelectorAll(tagName + "." + className);
} else {
var results = [];
var all = document.getElementsByTagName(tagName);
var regex = new Regexp("(?:^|\\s)" + tagName + "(?:\\s|$)");
for (var i=0, len=all.length; i<len; ++i) {
if (regex.test(all[i].className)) {
results.push(all[i]);
}
}
return results;
}
}
為什么每個人都使用選擇器? 已經有一個類附加到所有適當的元素,所以為什么不修改類?
此函數將查找給定名稱的類,並為該類設置屬性。 如果在不同的樣式表中有多個具有重合名稱的類,請小心,因為該功能不是!
function changeStyle(stylename,attribute,newvalue) {
var cssRules = 'rules';
if(document.styleSheets[0].cssRules) {
cssRules = 'cssRules';
}
for(var sheetId=0; sheetId<document.styleSheets.length; sheetId++) {
var sheet = document.styleSheets[sheetId];
for(var ruleId=0; ruleId<sheet[cssRules].length; ruleId++) {
var rule = sheet[cssRules][ruleId];
if(rule.selectorText == "."+stylename) {
rule.style.setProperty(attribute,newvalue,"");
}
}
}
return false;
}
現在,只需打電話
changeStyle('foo','display','none');
並且單元格應該消失,然后用'block'
來取回它們(IE不能做更近期的顯示樣式)。 我懷疑在一個表中你會想要隱藏整行而不僅僅是單元格,但你也可以通過設置hidden
visibility
來使它們消失 - 它們仍會占用空間,但不會占用空間。
看,沒有jquery,沒有自制元素選擇器。 只是有點惱人的javascript來循環遍歷樣式表及其規則......
像這樣的東西?
$("table td.specific_class").toggle();
/* Go through the table rows */
var trs = document.getElementsByTagName("tr");
for (var i = 0; i < trs.length; i++ ) {
var myClass, tds, line_done = false;
/* Go through the table cells */
tds = trs[i].getElementsByTagName("td");
for ( var k = 0; k < tds.length; k++ ){
/* Check each class of each cell */
myClasses = tds[k].className.split(' ');
for ( var j = 0; j < myClasses.length; j++ ){
/* If the class corresponds we toggle the row and break until the next row */
if ( myClasses[j].className == "foo" ){
trs[i].style.display = trs[i].style.display == "none" ? "block" : "none";
line_done = 1;
break;
}
}
if ( line_done ){
break;
}
}
}
td = document.getElementsByTagName('td');
for (var i = 0; i < td.length; i++) {
if (td[i].className === 'foo')
if (!td[i].style.display)
td[i].style.display = 'none';
else
td[i].style.display = '';
}
}
這樣的事情應該這樣做:
var trs = document.getElementsByTagName("tr");
for (var i in trs) {
var tr = trs[i];
if (tr.getElementsByClassName("foo").length > 0)
tr.style.display = (tr.style.display == "none" ? "block" : "none");
}
這將切換包含class =“foo”的子項的任何TR上的顯示。
試試這個
<html>
<head>
<title>test</title>
<script type="text/javascript">
var toggle = function (action) {
var trs = document.getElementById('bar').getElementsByTagName('tr'),
trs_count = trs.length,
needed = [],
total = 0,
pattern = /\bfoo\b/g,
initial= 'show';
for (i=0; i<trs_count; i++) {
var tds = trs[i].getElementsByTagName('td'),
tds_count = tds.length;
for (j=0; j<tds_count; j++) {
if (pattern.exec(tds[j].className)) {
needed.push(tds[j]);
total++;
}
}
}
toggle = function (action) {
if (this.display == null) {
this.display = initial;
}
if (action == null) {
this.display = (this.display == 'hide') ? 'show' : 'hide';
}
else {
this.display = action;
}
for (i=0; i<total; i++) {
if (this.display == 'show') {
needed[i].style.display = 'block';
}
else {
needed[i].style.display = 'none';
}
}
return true;
}
return toggle();
}
</script>
</head>
<body>
<table id="bar">
<tr><th>Header</th></tr>
<tr><td class="foo">1 Data foo</td></tr>
<tr><td>2 Data</td></tr>
<tr><td class="foo">3 Data foo</td></tr>
<tr><td>4 Data</td></tr>
</table>
<button type="button" onclick="toggle()">toggle</button>
</body>
</html>
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