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[英]How to get the app path name from an Xcode project on the command line?
[英]How to run an Xcode built app from the command line (bash)
繼我的問題如何從bash運行xcode項目?
我在構建目錄中找到了構建的* .app,但我正在試圖弄清楚如何讓xcode打開它,因為它不能僅僅作為Mac OS X程序運行。
有任何想法嗎?
感謝ch在這篇文章: iPhone的XCode測試自動化
我遇到了同樣的問題,試圖從構建我的xcode項目啟動我的調試輸出。 我只是嘗試以下
open ./prog.app&
似乎可以做到這一點。
我使用bash文件解決了我的問題,該文件使用rsync來同步工作目錄,然后使用AppleScript來構建和運行項目。
sync.sh:
#!/bin/bash
# script for moving development files into xcode for building
developmentDirectory="/"
xcodeDirectory="/"
echo 'Synchronising...'
rsync -r $developmentDirectory $xcodeDirectory \
--exclude='.DS_Store' --exclude='.*' --exclude='utils/' --exclude='photos'
echo 'Synchronising Done at:'
echo $(date)
buildandrun:
set projectName to "projectName"
# AppleScript uses : for / in directory paths
set projectDir to "Users:username:Documents:" & projectName & ":" & projectName & ".xcodeproj"
tell application "Xcode"
open projectDir
tell project projectName
clean
build
(* for some reasons, debug will hang even the debug process has completed.
The try block is created to suppress the AppleEvent timeout error
*)
try
debug
end try
end tell
quit
end tell
然后,最后,我在.bash_profile中使用名為run.sh的shell腳本:
run.sh:
#!/bin/bash
bash utils/sync.sh
osascript utils/buildandrun
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