[英]How to print source code lines in python logger
是否有一些相對簡單的方法以編程方式將源代碼行包含到python logger報告中。 例如...
import logging
def main():
something_is_not_right = True
logging.basicConfig(level=logging.DEBUG,
format=('%(filename)s: '
'%(levelname)s: '
'%(funcName)s(): '
'%(lineno)d:\t'
'%(message)s')
)
if something_is_not_right == True:
logging.debug('some way to get previous line of source code here?')
所以輸出看起來像這樣。
example.py: DEBUG: main(): 14: if something_is_not_right == True:
import inspect
import logging
import linecache
def main():
something_is_not_right = True
logging.basicConfig(level=logging.DEBUG,
format=('%(filename)s: '
'%(levelname)s: '
'%(funcName)s(): '
'%(lineno)d:\t'
'%(message)s')
)
if something_is_not_right:
logging.debug(linecache.getline(
__file__,
inspect.getlineno(inspect.currentframe())-1))
if __name__=='__main__':
main()
產量
test.py: DEBUG: main(): 18: if something_is_not_right == True:
只是因為我看到unutbu嘗試類似的東西,這是我想出的代碼(為時已晚,否則):
import logging, sys
# From logging.py
def currentframe():
"""Return the frame object for the caller's stack frame."""
try:
raise Exception
except:
return sys.exc_traceback
f = open(__file__.rstrip('c'))
owncode = f.readlines()
f.close()
def main():
something_is_not_right = True
logging.basicConfig(level=logging.DEBUG,
format=('%(filename)s: '
'%(levelname)s: '
'%(funcName)s(): '
'%(lineno)d:\t'
'%(message)s')
)
if something_is_not_right == True:
prev = owncode[currentframe().tb_frame.f_back.f_lineno - 2]
logging.debug('previous line of source code here:\n%s' % prev)
if __name__ == '__main__':
main()
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