需要一個快速的bash腳本

Question

我在同一個父目錄中大約有100個目錄，它們遵循命名約定[sitename] .com。 我想將它們全部重命名為[sitename] .subdomain.com。

這是我嘗試過的：

for FILE in `ls | sed 's/.com//' | xargs`;mv $FILE.com $FILE.subdomain.com;

但是它失敗了。 有任何想法嗎？

Answer 1

使用named（1） 。

rename .com .subdomain.com *.com

如果您有一個perl重命名而不是普通的重命名 ，則可以使用：

rename s/\\.com$/.subdomain.com/ *.com

Answer 2

使用bash：

for i in *
do
    mv $i ${i%%.com}.subdomain.com
done

$ {i %%。com}構造返回不帶“ .com”后綴的i的值。

Answer 3

find . -name '*.com' -type d -maxdepth 1 \
| while read site; do
    mv "${site}" "${site%.com}.subdomain.com"
  done

Answer 4

關於什么：

ls |
grep -Fv '.subdomain.com' |
while read FILE; do
  f=`basename "$FILE" .com`
  mv $f.com $f.subdomain.com
done

Answer 5

參見： http : //blog.ivandemarino.me/2010/09/30/Rename-Subdirectories-in-a-Tree-the-Bash-way

#!/bin/bash
# Simple Bash script to recursively rename Subdirectories in a Tree.
# Author: Ivan De Marino <ivan.demarino@betfair.com>
#
# Usage:
#    rename_subdirs.sh <starting directory> <new dir name> <old dir name>

usage () {
   echo "Simple Bash script to recursively rename Subdirectories in a Tree."
   echo "Author: Ivan De Marino <ivan.demarino@betfair.com>"
   echo
   echo "Usage:"
   echo "   rename_subdirs.sh <starting directory> <old dir name> <new dir name>"

   exit 1
}

[ "$#" -eq 3 ] || usage

recursive()
{
   cd "$1"
   for dir in *
   do
      if [ -d "$dir" ]; then
         echo "Directory found: '$dir'"
         ( recursive "$dir" "$2" "$3" )
         if [ "$dir" == "$2" ]; then
            echo "Renaming '$2' in '$3'"
            mv "$2" "$3"
         fi;
      fi;
   done
}

recursive "$1" "$2" "$3"

Answer 6

嘗試這個：

for FILE in `ls -d *.com`; do
  FNAME=`echo $FILE | sed 's/\.com//'`;
  `mv $FILE $FNAME.subdomain.com`;
done