PHP / MySQL-創建不同值的數組，查詢數據庫表以獲取與這些值相關的數據，並為每個值循環

Question

我不是一個PHP程序員，所以我希望有人可以幫助我。 我想做的是從競爭對手列中獲取不同的值，創建它們的數組，基於許多變量為每個不同的值檢索share1-share12值，然后輸出競爭對手及其share1- 12個值。

以下是我的數據表的格式以及我一起整理的一堆代碼：

狀態|大貓|競爭對手|度​​量標准| share1 | share2 | share3 | share4 | share5 | share6 | share7 | share8 | share9 | share10 | share11 | share12

<?php
    $product = $_GET['product'];
    $cat = $_GET['cat'];
    $state = $_GET['state'];
    $metric = $_GET['metric'];

    $table = $product ."_specs_states";

    $q = " SELECT distinct(competitor) as competitor from $table";
                $result = $dbc->query($q) or die("unable to execute the query<br />" . $dbc->errno . "<br />" . $dbc->error);
                $r = $result->fetch_array();
                $competitors = array();

                do {
                    $competitors[] = $r[0];

          } while ($r = $result->fetch_array());
          echo $competitors;


        foreach($competitors as $competitor){


                $q = "SELECT * FROM $table where state = '$state' && bigcat = '$cat' && product = '$product' && metric = '$metric' && competitor = '$competitor'";
                $result = $dbc->query($q) or die("unable to execute the query<br />" . $dbc->errno . "<br />" . $dbc->error);

                $r = $result->fetch_array();

                    $share1 = ($r[5]);
                    $share2 = ($r[6]);
                    $share3 = ($r[7]);
                    $share4 = ($r[8]);
                    $share5 = ($r[9]);
                    $share6 = ($r[10]);
                    $share7 = ($r[11]);
                    $share8 = ($r[12]);
                    $share9 = ($r[13]);
                    $share10 = ($r[14]);
                    $share11 = ($r[15]);
                    $share12 = ($r[16]);

    }//end loop

    ?>

    <?php
    $i=1;
    while($i<=#)
      {
    ?>

    <?= $competitor ?><br />
    <?= $share1 ?><br />
    <?= $share2 ?><br />
    <?= $share3 ?><br />
    <?= $share4 ?><br />
    <?= $share5 ?><br />
    <?= $share6 ?><br />
    <?= $share7 ?><br />
    <?= $share8 ?><br />
    <?= $share9 ?><br />
    <?= $share10 ?><br />
    <?= $share11 ?><br />
    <?= $share12 ?>


    <?php
      $i++;
      }
    ?>

Answer 1

我不太了解，但我想您想輸出所有競爭對手和他們的股份，但這只是輸出最后一個競爭對手？ 如果是這樣，解決該問題的方法是將您的回聲放入foreach循環中，而不是創建另一個while循環。

<?php
$product = $_GET['product'];
$cat = $_GET['cat'];
$state = $_GET['state'];
$metric = $_GET['metric'];

$table = $product ."_specs_states";

$q = " SELECT distinct(competitor) as competitor from $table";
            $result = $dbc->query($q) or die("unable to execute the query<br />" . $dbc->errno . "<br />" . $dbc->error);
            $r = $result->fetch_array();
            $competitors = array();

            do {
                $competitors[] = $r[0];

      } while ($r = $result->fetch_array());
      echo $competitors;


    foreach($competitors as $competitor){


            $q = "SELECT * FROM $table where state = '$state' && bigcat = '$cat' && product = '$product' && metric = '$metric' && competitor = '$competitor'";
            $result = $dbc->query($q) or die("unable to execute the query<br />" . $dbc->errno . "<br />" . $dbc->error);

            $r = $result->fetch_array();

                $share1 = ($r[5]);
                $share2 = ($r[6]);
                $share3 = ($r[7]);
                $share4 = ($r[8]);
                $share5 = ($r[9]);
                $share6 = ($r[10]);
                $share7 = ($r[11]);
                $share8 = ($r[12]);
                $share9 = ($r[13]);
                $share10 = ($r[14]);
                $share11 = ($r[15]);
                $share12 = ($r[16]);

                echo $competitor ."<br />";
echo $share1 ."<br />";
echo $share2 ."<br />";
echo $share3 ."<br />";
echo $share4 ."<br />";
echo $share5 ."<br />";
echo $share6 ."<br />";
echo $share7 ."<br />";
echo $share8 ."<br />";
echo $share9 ."<br />";
echo $share10 ."<br />";
echo $share11 ."<br />";
echo $share12;

}//end loop

?>