手勢識別器和按鈕操作

Question

我有一個看起來像這樣的視圖層次結構：

UIView (A)
UIView > UIImageView
UIView > UIView (B)
UIView > UIView (B) > Rounded Rect Button
UIView > UIView (B) > UIImageView
UIView > UIView (B) > UILabel

我已將手勢識別器附加到我的 UIView (B) 上。 我面臨的問題是，我沒有對 UIView (B) 內的圓角矩形按鈕執行任何操作。 singleTap 手勢識別器捕獲/覆蓋按鈕的 Touch Up Inside 事件。

我怎樣才能讓它工作？ 我認為響應者鏈層次結構將確保優先考慮按鈕觸摸事件，並且它會被觸發！ 我錯過了什么？

這是一些相關的代碼：

#pragma mark -
#pragma mark View lifecycle (Gesture recognizer setup)

- (void)viewDidLoad {
    [super viewDidLoad];

    // double tap gesture recognizer
    UITapGestureRecognizer *dtapGestureRecognize = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(doubleTapGestureRecognizer:)];
    dtapGestureRecognize.delegate = self;
    dtapGestureRecognize.numberOfTapsRequired = 2;
    [self.viewB addGestureRecognizer:dtapGestureRecognize];

    // single tap gesture recognizer
    UITapGestureRecognizer *tapGestureRecognize = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(singleTapGestureRecognizer:)];
    tapGestureRecognize.delegate = self;
    tapGestureRecognize.numberOfTapsRequired = 1;
    [tapGestureRecognize requireGestureRecognizerToFail:dtapGestureRecognize];
    [self.viewB addGestureRecognizer:tapGestureRecognize];

    // add gesture recodgnizer to the grid view to start the edit mode
    UILongPressGestureRecognizer *pahGestureRecognizer = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressGestureRecognizerStateChanged:)];
    pahGestureRecognizer.delegate = self;
    pahGestureRecognizer.minimumPressDuration = 0.5;
    [self.viewB addGestureRecognizer:pahGestureRecognizer];

    [dtapGestureRecognize release];
    [tapGestureRecognize release];
    [pahGestureRecognizer release];
}

#pragma mark -
#pragma mark Button actions

- (IBAction)buttonTouchUpInside:(id)sender {
    NSLog(@"%s, %@", __FUNCTION__, sender);
}

#pragma mark -
#pragma mark Gesture recognizer actions


- (void)singleTapGestureRecognizer:(UIGestureRecognizer *)gestureRecognizer {
    NSLog(@"%s", __FUNCTION__);
}

- (void)doubleTapGestureRecognizer:(UIGestureRecognizer *)gestureRecognizer {
    NSLog(@"%s", __FUNCTION__);
}

- (void)longPressGestureRecognizerStateChanged:(UIGestureRecognizer *)gestureRecognizer {

    switch (gestureRecognizer.state) {

        case UIGestureRecognizerStateEnded: {
            NSLog(@"%s", __FUNCTION__);

            break;
        }
        default:
            break;
    }
}

Answer 1

在“shouldReceiveTouch”方法中，您應該添加一個條件，如果觸摸位於按鈕中，則該條件將返回 NO。

這是來自蘋果SimpleGestureRecognizers 的例子。

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {

    // Disallow recognition of tap gestures in the segmented control.
    if ((touch.view == yourButton)) {//change it to your condition
        return NO;
    }
    return YES;
}

希望它會有所幫助

編輯

正如丹尼爾指出的那樣，您必須符合UIGestureRecognizerDelegate才能使其工作。

沙尼

Answer 2

我也有同樣的問題，然后我嘗試

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch{

    if ([touch.view isKindOfClass:[UIButton class]]) {      //change it to your condition
        return NO;
    }
    return YES;
}

它現在完美地工作.......

Answer 3

一般來說，我們使用下面的委托方法來避免各種 UIControl 中的觸摸：

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    if (([touch.view isKindOfClass:[UIControl class]])) {
         return NO;
    }
    return YES;
}

注意：不要做這個檢查（檢查recognizer.view 類類型）gestureRecognizerShouldBegin，它不會工作。

Answer 4

這是一個Swift 3.0版本：

extension UIViewController: UIGestureRecognizerDelegate {

public func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
    if touch.view is UIButton {
        return false
    }
    return true
}

不要忘記：

Make your tapper object delegate to self (eg: tapper.delegate = self)

Answer 5

這是一個 Swift 版本：

func gestureRecognizer(gestureRecognizer: UIGestureRecognizer, shouldReceiveTouch touch: UITouch) -> Bool {
    if (touch.view!.isKindOfClass(UIButton)) {
        return false
    }
    return true
}

不要忘記：

1. 讓你的類符合UIGestureRecognizerDelegate
2. 使您的 Tapper 對象委托給 self （例如： tapper.delegate = self ）

Answer 6

我認為最好的解決方案是使用下面的代碼片段：

-(BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch {
    CGPoint touchLocation = [touch locationInView:self.view];
    return !CGRectContainsPoint(self.menuButton.frame, touchLocation);
}

Answer 7

Vivienne 的 Swift 版本回答：

func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldReceive touch: UITouch) -> Bool {
    let location = touch.location(in: view)
    return !someView.frame.contains(location)
}