如何在SQL Server中獲取日期時間差的值

Question

有誰知道如何獲取SQL Server中日期時間差的值？

例如：

如果我有一個表，請致電客戶，並在下面的列中

Name    Join_Date             Exp_Date 
Alvin   2010-01-01 12:30:00   2010-01-03 11:30:00 
Amy     2010-01-01 15:30:00   2010-01-02 10:30:00

如何在SQL Server中獲得以下結果？

Name    Join_Date             Exp_Date                Diff
Alvin   2010-01-01 12:30:00   2010-01-03 11:30:00     2days 1hour
Amy     2010-01-01 15:30:00   2010-01-02 10:30:00     1day 7hours

Answer 1

Select Name, Join_Date, Exp_Date
    , DateDiff(d, Join_Date, Exp_Date) As [Days]
    , DateDiff(hh, Join_Date, Exp_Date) As [Hours]

要么

Select Name, Join_Date, Exp_Date
    , Cast( DateDiff(d, Join_Date, Exp_Date) As varchar(10) ) + ' days ' 
        + Cast( DateDiff(hh, Join_Date, Exp_Date)  As varchar(10) ) + ' hours'

或超級花哨的版本

Select Name, Join_Date, Exp_Date
    , Cast( DateDiff(d, Join_Date, Exp_Date) As varchar(10) ) 
        + Case
            When DateDiff(d, Join_Date, Exp_Date) = 1 Then ' day '
            Else ' days '
            End
        + Cast( DateDiff(hh, Join_Date, Exp_Date)  As varchar(10) ) 
        + Case
            When DateDiff(hh, Join_Date, Exp_Date) = 1 Then ' hour'
            Else ' hours '
            End

Answer 2

使用DATEDIFF： http ： //msdn.microsoft.com/en-us/library/aa258269（ v = sql.80） .aspx

Answer 3

我的解決方案假定您想要英文的日期/時間零件名稱，並使用UDF。

它計算日期時間之間的實際時差，即，如果Exp_Date是今天，而Join_Date是昨天，但它們之間的間隔少於24小時，則天數將為0 。 零零件不顯示。

CREATE FUNCTION dbo.fnGetDTPart (@UnitName varchar(10), @Number int)
RETURNS varchar(50)
AS BEGIN
  DECLARE @Result varchar(50);
  IF @Number = 0
    SET @Result = ''
  ELSE
    SET @Result = CAST(@Number AS varchar) + @UnitName +
      CASE @Number WHEN 1 THEN ' ' ELSE 's ' END;
  RETURN @Result;
END
GO


WITH Customer (Name, Join_Date, Exp_Date) AS (
  SELECT
    'Alvin',
    CAST('2010-01-01 12:30:00' AS datetime),
    CAST('2010-01-03 11:30:00' AS datetime)
  UNION
  SELECT
    'Amy',
    CAST('2010-01-01 15:30:00' AS datetime),
    CAST('2010-01-02 10:30:00' AS datetime)
)
SELECT
  Name,
  Join_Date,
  Exp_Date,
  Diff =
    dbo.fnGetDTPart('year',   DATEPART(year,   DiffDT)-1900) +
    dbo.fnGetDTPart('month',  DATEPART(month,  DiffDT)-1) +
    dbo.fnGetDTPart('day',    DATEPART(day,    DiffDT)-1) +
    dbo.fnGetDTPart('hour',   DATEPART(hour,   DiffDT)) +
    dbo.fnGetDTPart('minute', DATEPART(minute, DiffDT)) +
    dbo.fnGetDTPart('second', DATEPART(second, DiffDT))
FROM (
  SELECT
    Name,
    Join_Date,
    Exp_Date,
    DiffDT = Exp_Date - Join_Date
  FROM Customer
) s

Answer 4

假設您想要實際的正確日期差（如Andriy M的評論中所述），並且只是希望以一種用戶友好的方式顯示它，則可以執行以下操作：

select  Join_Date
        ,Exp_Date
        ,cast((datediff(hour,Join_Date,Exp_Date) / 24) as nvarchar) + 'days ' 
        + cast((datediff(hour,Join_Date,Exp_Date) % 24) as nvarchar) + 'hours' as Diff