從列表中刪除與條件匹配的第一個匹配項

Question

假設我有一個字符串列表：

first item
second item
# first commented item
third item
# second commented item

如何從列表中刪除以#開頭的第一個項目？

預期結果：

first item
second item
third item
# second commented item

Answer 1

>>> items = ["First", "Second", "# First", "Third", "# Second"]
>>> for e in items:
...     if e.startswith('#'):
...             items.remove(e)
...             break
... 
>>> items
['First', 'Second', 'Third', '# Second']

Answer 2

items = ["First", "Second", "# First", "Third", "# Second"]
for i in xrange(len(items)):
    if items[i][0] == '#':
        items.pop(i)
        break
print items