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[英]Throw Exception, message passed into constructor won't appear in PHP error
[英]Throw an exception with the SQL error message
我在此代碼中出現錯誤:
try
{
$db = parent::getConnection();
if($this->id == 0 )
{
$query = 'insert into articles (modified, username, url, title, description, points )';
$query .= " values ('$this->getModified()', '$this->username', '$this->url', '$this->title', '$this->description', '$this->points' )";
}
else if($this->id != 0)
{
$query = "update articles set modified = CURRENT_TIMESTAMP, username = '$this->username', url = '$this->url', title = '$this->title', description = '$this->description', points = '$this->points', ranking = '$this->ranking' where id = '$this->id' ";
}
$lastid = parent::execSql2($query);
if($this->id == 0 )
$this->id = $lastid;
}
catch(Exception $e){
error_log($e);
}
我必須添加什么才能得到一些有意義的SQL錯誤消息?
(對於某些查詢,似乎沒有獲得用戶名)
編輯:我收到此錯誤日志:
[18-Mar-2011 05:19:13] exception 'Exception' in /home1/mexautos/public_html/kiubbo/data/model.php:90
Stack trace:
#0 /home1/mexautos/public_html/kiubbo/data/article.php(276): Model::execSQl2('update articles...')
#1 /home1/mexautos/public_html/kiubbo/data/article.php(111): Article->save()
#2 /home1/mexautos/public_html/kiubbo/pages/frontpage.php(21): Article->calculateRanking()
#3 /home1/mexautos/public_html/kiubbo/pages/frontpage.php(27): FrontPage->updateRanking()
#4 /home1/mexautos/public_html/kiubbo/index.php(15): FrontPage->showTopArticles('426')
#5 {main}
謝謝,
問候,
卡洛斯
解決此問題的最佳方法是使用數據庫處理程序將引發的自定義異常。
class DatabaseErrorException{
public function __construct( $errorMesssage, $query ){
throw new Exception( $errorMessage . " for query: " . $query );
}
}
因此,您可以在數據庫庫中檢測錯誤並從那里拋出錯誤,或者在try語句中可以擁有:
if( $db->someError )
throw new DatabaseErrorException( $db->someError, $query );
然后您的catch語句將變成
catch( DatabaseErrorException $e ){
error_log( $e->getMessage( ) );
//Or whatever handling you wish to do with it.
}
error_log('Failed to set record in articles table: '.
$e->getMessage().
"\n".$query
);
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