PHP返回是否會像break一樣退出？

Question

我當時在看這個函數，注意到有一些返回.... php返回是離開該函數還是繼續向下直到底部

function confirmUser($username, $password) {
    global $conn; /* Add slashes if necessary (for query) */
    if (!get_magic_quotes_gpc()) {
        $username = addslashes($username);
    }

    /* Verify that user is in database */
    $q = "select password from users where username = '$username'";
    $result = mysql_query($q, $conn);
    if (!$result || (mysql_numrows($result) < 1)) {
        return 1; //Indicates username failure
    }

    /* Retrieve password from result, strip slashes */
    $dbarray = mysql_fetch_array($result);
    $dbarray['password'] = stripslashes($dbarray['password']);
    $password = stripslashes($password);

    /* Validate that password is correct */
    if ($password == $dbarray['password']) {
        return 0; //Success! Username and password confirmed
    } else {
        return 2; //Indicates password failure
    }
}

Answer 1

它立即將函數留在它所調用的位置。

Answer 2

從函數返回。 查看文檔-http: //php.net/return