將StringIO對象轉換為Django ImageFile

Question

我正在嘗試從StringIO（或更具體地說是cStringIO）獲取數據並將其轉換為django.core.files.images.ImageFile。

但它不起作用。 不管怎樣，我的意思是它在很多方面都失敗了，谷歌讓我失望了。

到目前為止我有：

pi = ProductImage(product=product)
image = ImageFile(image_file)
image.name = image_name # defined elsewhere
pi.source_image.save(image_name, image)
pi.save()

我的堆棧跟蹤如下：

File "dev.py", line 359, in process_csv_item
  pi.source_image.save(image_name, image)
File "C:\Python26\lib\site-packages\django\db\models\fields\files.py", line 92, in save
  self.name = self.storage.save(name, content)
File "C:\Python26\lib\site-packages\django\core\files\storage.py", line 48, in save
  name = self._save(name, content)
File "C:\Python26\lib\site-packages\django\core\files\storage.py", line 168, in _save
  for chunk in content.chunks():
File "C:\Python26\lib\site-packages\django\core\files\base.py", line 65, in chunks
  counter = self.size
File "C:\Python26\lib\site-packages\django\core\files\base.py", line 39, in _get_size
  elif os.path.exists(self.file.name):
AttributeError: 'cStringIO.StringI' object has no attribute 'name'

我在哪里可以看下一個？

Answer 1

使用django.core.files.base.ContentFile（image_file）：

pi = ProductImage(product=product)
pi.source_image.save(image_name, ContentFile(image_file.read()))
pi.save()