如何在一個頁面中將變量從一個函數傳遞給另一個函數？

Question

好的，現在我有另一個問題，我想從一個函數向另一個函數發送一個或多個變量，如下所示：

class test{

    var $text2;

    function text1($text1){ // This will catch "This is text" from $text variable.

        $text1 = $this -> text2; // Giving $text1 value to $text2 

        return $this -> text2; // Now here is the trouble i think, i want to send the variable to the next function that is text2(). How do i do that?

    }
    function text2($text2){ // Here is the place that says undefined variable i want the variable $text2 from function text1() to be called here.

        echo $text2; // Now the variable $text2 should echo "This is text".

    }
}

$test = new test();

$text1 = "This is text"; // Assigning value to the variable.

$test -> text1($text1); // Passing the variable as parameter in the function text1().

echo $test -> text2($text2); // Trying to display the value of $text2 that is "This is text".

Answer 1

@其他大多數答案的作者：為什么您只接受不良代碼並重新使用它，而不指出明顯的不良做法？

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您的代碼有麻煩，主要是因為它很難閱讀！ 您的函數和變量具有相同的名稱，這很不好 ，它們通常是不好的變量和函數名稱！

• 函數名稱中應該有一個“動作詞”，一個動詞來表明它們的作用
• 變量名稱不應包含數字
• 變量名稱應描述一個容器
• 數據類型導致錯誤的變量名（$ string，$ text，$ int）

這是一個類的示例，由於@Matteo Riva的評論，我在“ TextPuzzler”中命名。

class TextPuzzler
{
    protected $myText;

    public function setMyText($text)
    {
        $this->myText = $text;
    }

    public function getMyText()
    {
        return $this->myText;
    }

    public function printMyText()
    {
        echo $this->myText;
    }
}

$puzzler = new TextPuzzler();

$text = "This is a random text";

//this is how you set your text
$puzzler->setMyText($text);

//this is how you echo it via a special echo function, not really needed ...
$puzzler->printMyText();

//... because you can also use the getter and echo it like this
echo $puzzler->getMyText();

Answer 2

它不是函數，而是類方法。 您不必在類內部傳遞任何內容，只需要設置類變量

Answer 3

Markus指出的問題是，變量名和函數名之間存在沖突。 同樣，在函數text1，php中，而不是在smalltalk中，分配是向后的。

Answer 4

嘗試這個

課堂測試{

var $ text2;

function text1（$ text1）{//這將從$ text變量中捕獲“ This is text”。

 $text2 = $text1; // Giving $text1 value to $text2 $this->text2($text2); 

}

函數text2（$ text2）{

 echo $text2; // Now the variable $text2 should echo "This is text". 

}

}

$ test =新的test（）;

$ text1 =“這是文本”; //為變量分配值。

$ test-> text1（$ text1）; //在函數text1（）中將變量作為參數傳遞。

$ test-> text2（$ text2）; //試圖顯示$ text2的值為“ This is text”。

Answer 5

我認為您只是有一個分配錯誤。

在text1函數中嘗試以下操作

function text1($text1){ // This will catch "This is text" from $text variable.

        $this->text2 = $text1; //CHANGE HERE

        return $this->text2; 

}

function text2(){ //CHANGE HERE
        echo $this->text2;
}

分配從右到左進行。

左=右;

左側將獲得右側的值。

Answer 6

當您創建text1函數時，我認為代碼應該像這樣

var $text2;

function text1（$ text1）{//這將從$ text變量中捕獲“ This is text”。

text2 = $text1; // Giving $text1 value to $text2 

return text2; // Now here is the trouble i think, i want to send the variable to the next function that is text2(). How do i do that?

}

function text2($text2){ // Here is the place that says undefined variable i want the variable $text2 from function text1() to be called here.

    echo $text2; // Now the variable $text2 should echo "This is text".

}

還有一件事$ text2應該是global var