PHP array_search

Question

是否有任何函數可以用作為數組的$ needle完成與array_search等效的功能？ 就像，這將是一個理想的解決方案：

$needle = array('first', 'second');
$haystack = array('fifth','second','third', 'first');

// Returns key 1 in haystack
$search = array_search( $needle, $haystack );

如果沒有函數，是否還有其他可以接受指針的函數，這些指針可能是我可以用來創建自定義函數的數組？

Answer 1

這可能有助於構建您的功能：

$intersection = array_intersect($needle, $haystack);

if ($intersection) // $haystack has at least one of $needle

if (count($intersection) == count($needle)) // $haystack has every needle

Answer 2

您可以使用array_intersect（）： http : //php.net/manual/en/function.array-intersect.php

if (empty(array_intersect($needle, $haystack)) {
   //nothing from needle exists in haystack
}

Answer 3

$needle = array('first', 'second');
$haystack = array('fifth','second','third', 'first');

// Returns key 1 in haystack


function array_needle_array_search($needle, $haystack)
{
        $results = array();
        foreach($needle as $n)
        {
                $p = array_search($n, $haystack);
                if($p)
                    $results[] = $p;
        }
        return ($results)?$results:false;
}

print_r(array_needle_array_search($needle, $haystack));

Answer 4

$needle = array('first', 'second');
$haystack = array('fifth','second','third', 'first');

if(in_array($needle, $haystack)) {
     echo "found";
}