根據會話選擇

Question

如何從用戶名基於會話的數據庫中選擇一個值？

這是我到目前為止的內容：

$query = mysql_query ("select id from CUSTOMER where username = .$_SESSION['username'] ");

Answer 1

如果用戶名在會話cookie中，則像這樣獲取用戶名

$username = $_SESSION['username'];
$escuname = mysql_real_escape_string($username);
$query = mysql_query("select id from CUSTOMER where username = '".$escuname."' LIMIT 1"); 

Answer 2

$query = mysql_query("select id from CUSTOMER where username = '".$_SESSION['username']."'");

Answer 3

您查詢中的會話變量未正確解析。 您可以使用大括號語法來修復它：

$query = mysql_query( "select id from CUSTOMER where username = '{$_SESSION[ "username" ]}'" );

或使用點運算符將其連接：

$query = mysql_query ( "select id from CUSTOMER where username = '" . $_SESSION[ "username" ] . "'" );

您可以在PHP手冊中找到有關解析字符串的更多信息。