在textarea中輸入的內容不會在mysql表中更新

Question

我創建了一個表格來更新我網站上的橫幅信息。 除了鍵入稱為“ desc”的“ textarea”中的輸入外，所有內容似乎都在更新。 代碼看起來不錯，這讓我發瘋。

提前致謝。

<html>
<body>



<form action="aupdate.php" method="POST" enctype="multipart/form-data">

    Your or your company's name:<br>
    <input type="text" name="com" size="60"><br>


    URL:<br>
    <input type="text" name="url" size="80"><br>


    Please enter the username that you will use to update your advertisement info:<br>
    <input type="text" name="user" size="80"><br>

    Please enter the password that you will use to update your advertisement info:<br>
    <input type="text" name="pass" size="80"><br>

   <br>
   <br>


<br>
    File:<br>
    <input type="file" name="image">

          advertisement description:<br>

 <textarea name="desc" id="desc" cols="35" rows="5" ></textarea>

      <input type="submit" value="update your ad!">


    </form>

<?php

//connect to database
require("connect.php");

//get user made username
$user = $_POST['user'];

//get user made password
$pass = $_POST['pass'];

//encrypt user made password
$encpass = hash('sha256', $pass);

//file properties
$file = $_FILES['image']['tmp_name'];

//initialize company name and description
$com = $_POST['com'];
$desc = $_POST['desc'];
$url = $_POST['url'];




//check to see if coupon code and other essential info entered
if (!$user || !$pass )
{
    echo "Please enter updated info with username and password.";
}
else
{

//retrieve data from password table
$query = mysql_query ("SELECT * FROM apartment WHERE pass = '$encpass' ");

//get number of rows in table
$numrows = mysql_num_rows ($query);

//check if code is right or exists
if ($numrows !=0)
{

    // code to login
    while ($row = mysql_fetch_assoc ($query))
    {
        //retrieve code from database to match with the code that was put into field
        $dbuser = $row['user'];
        $dbpass = $row['pass'];
    }

    //check to see if they match
    if ($user == $dbuser && $encpass == $dbpass )
    {


    //check to see if a file has even been submitted
    if (!$file)
    {

        echo "please upload image";
    }
    else
    {
        //get image file attributes
    $image = addslashes(file_get_contents ($_FILES['image']['tmp_name']));
    $image_name = addslashes($_FILES['image']['name']);
    $image_size = addslashes(getimagesize($_FILES['image']['tmp_name']));

    //check if image file size is right
    if ($image_size==FALSE)
        echo "that's not an image.";
    else
    {


mysql_query ("UPDATE apartment SET desc = '$desc' WHERE user ='$user'"); 
mysql_query ("UPDATE apartment SET name = '$image_name' WHERE user ='$user'"); 
mysql_query ("UPDATE apartment SET com = '$com' WHERE user ='$user'"); 
mysql_query ("UPDATE apartment SET url = '$url' WHERE user ='$user'"); 
mysql_query ("UPDATE apartment SET image = '$image' WHERE user ='$user'"); 


            echo "advertisement successfully updated!";



    }
  }


}
else


    echo "Incorrect username or password.";
}
else 



    echo "Incorrect username or password.";

}

?>
</body>
</html>

Answer 1

desc是mysql保留字，用反引號引起來

並使用mysql_real_escape_string逃避用戶輸入

    $desc=mysql_real_escape_string($desc);
    mysql_query ("UPDATE apartment SET `desc` = '$desc' WHERE user ='$user'");

您也可以使用逗號分隔更新查詢中的字段來改進更新查詢以一次更新

mysql_query ("UPDATE apartment SET `desc` = '$desc',url='$url' WHERE user ='$user'");

在textarea中輸入的內容不會在mysql表中更新

問題描述

1 個解決方案

解決方案1
4 已采納 2011-04-20 06:50:43

在textarea中輸入的內容不會在mysql表中更新

問題描述

1 個解決方案

解決方案1 4 已采納 2011-04-20 06:50:43

解決方案1
4 已采納 2011-04-20 06:50:43