[英]Why am I getting a Segmentation Fault here?
#include <stdio.h>
#include <pthread.h>
#include <time.h>
#include <stdlib.h>
typedef struct pr_struct{
int owner;
int burst_time;
struct pr_struct *next_prcmd;
} prcmd_t;
static prcmd_t *pr_head = NULL;
static prcmd_t *pr_tail = NULL;
static int pending_request = 0;
static pthread_mutex_t prmutex = PTHREAD_MUTEX_INITIALIZER;
int add_queue(prcmd_t *node)
{
pthread_mutex_lock(&prmutex);
//code
prcmd_t *curNode = pr_head;
if(pr_head == NULL) { pr_head = node; return;}
while(curNode->next_prcmd)
{
curNode->next_prcmd = (prcmd_t*)malloc(sizeof(prcmd_t));
curNode = curNode->next_prcmd;
}
curNode->next_prcmd = node;
//
pending_request++;
pthread_mutex_unlock(&prmutex);
return(0);
}
int main()
{
if (pr_head == NULL)
{
printf("List is empty!\n");
}
prcmd_t *pr1;
pr1->owner = 1;
pr1->burst_time = 10;
add_queue(pr1);
prcmd_t *curNode = pr_head;
while(curNode->next_prcmd)
{
printf("%i\n", curNode->owner);
curNode = curNode->next_prcmd;
}
}
編輯:
這就是我現在所擁有的...
int main()
{
prcmd_t *pr1;
pr1 = (prcmd_t*)malloc(sizeof(prcmd_t));
pr1->owner = 1;
pr1->burst_time = 10;
if (pr_head == NULL)
{
printf("List is empty!\n");
}
add_queue(pr1);
prcmd_t *curNode = pr_head;
printf("made it here 1\n");
while(curNode->next_prcmd)
{
printf("in the while loop\n");
printf("%i\n", curNode->owner);
curNode = curNode->next_prcmd;
}
}
輸出為:列表為空! 在這里1
pr1
是prcmd_t struct
的未初始化指針,取消引用未初始化指針會導致未定義行為 。
您需要為堆/堆棧上的結構分配空間(取決於將在何處使用),因此一種選擇是:
// Allocate on stack
prcmd_t pr1;
pr1.owner = 1;
pr1.burst_time = 10;
add_queue(&pr1);
第二個是:
//Allocae on heap
prcmd_t *pr1;
pr = (prcmd_t*)malloc(sizeof(prcmd_t));
pr1->owner = 1;
pr1->burst_time = 10;
add_queue(pr1);
修改您的主要方法(僅主要方法)為:
int main()
{
if (pr_head == NULL)
{
printf("List is empty!\n");
}
prcmd_t *pr1;
pr1 = (prcmd_t*)malloc(sizeof(prcmd_t));
pr1->owner = 1;
pr1->burst_time = 10;
add_queue(pr1);
prcmd_t *curNode = pr_head;
while(curNode && curNode->owner)
{
printf("%i\n", curNode->owner);
curNode = curNode->next_prcmd;
}
}
產出
List is empty!
1
如果您不告訴我們在哪里,很難告訴您...
但
馬里奧
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