解析JSON字符串的最簡單方法

Question

如何將JSON字符串從一個鍵導航到另一個嵌套鍵並獲取值？ 我有以下字符串

{ "data" : { "current_condition" : [ { "cloudcover" : "75",
            "humidity" : "29",
            "observation_time" : "07:59 PM",
            "precipMM" : "0.0",
            "pressure" : "1011",
            "temp_C" : "19",
            "temp_F" : "67",
            "visibility" : "16",
            "weatherCode" : "116",
            "weatherDesc" : [ { "value" : "Partly Cloudy" } ],
            "weatherIconUrl" : [ { "value" : "http://www.worldweatheronline.com/images/wsymbols01_png_64/wsymbol_0002_sunny_intervals.png" } ],
            "winddir16Point" : "N",
            "winddirDegree" : "350",
            "windspeedKmph" : "26",
            "windspeedMiles" : "16"
          } ],
      "request" : [ { "query" : "01801",
            "type" : "Zipcode"
          } ],
      "weather" : [ { "date" : "2011-05-09",
            "precipMM" : "0.0",
            "tempMaxC" : "19",
            "tempMaxF" : "65",
            "tempMinC" : "10",
            "tempMinF" : "50",
            "weatherCode" : "113",
            "weatherDesc" : [ { "value" : "Sunny" } ],
            "weatherIconUrl" : [ { "value" : "http://www/images/wsymbols01_png_64/wsymbol_0001_sunny.png" } ],
            "winddir16Point" : "NNW",
            "winddirDegree" : "348",
            "winddirection" : "NNW",
            "windspeedKmph" : "24",
            "windspeedMiles" : "15"
          },
          { "date" : "2011-05-10",
            "precipMM" : "0.1",
            "tempMaxC" : "13",
            "tempMaxF" : "56",
            "tempMinC" : "12",
            "tempMinF" : "53",
            "weatherCode" : "122",
            "weatherDesc" : [ { "value" : "Overcast" } ],
            "weatherIconUrl" : [ { "value" : "http://www/images/wsymbols01_png_64/wsymbol_0004_black_low_cloud.png" } ],
            "winddir16Point" : "NNE",
            "winddirDegree" : "12",
            "winddirection" : "NNE",
            "windspeedKmph" : "31",
            "windspeedMiles" : "19"
          }
        ]
    } }

所以我回答我自己的問題：如果其他人想要快速獲得價值：這就是我想要的。

JSONObject j = new JSONObject(strResponse);

String weatherDesc = jObject.getJSONObject("data").getJSONArray("weather").getJSONObject(0).getJSONAr­ray("weatherDesc").getJSONObject(0).getString("value");

Answer 1

幾乎所有語言都有JSON庫。 如果你建議一個，我可能會指出你的一些事情。

與此同時，這里有幾個：

• Perl JSON庫
• Python是內置的
• Javascript在JSON中序列化其對象，因此它非常簡單
• C＃庫 - 也可以看到C＃ - 將json格式的數據解析為嵌套的哈希表
• 這是Android JSON參考

等等。 我建議快速谷歌選擇您的語言。

Answer 2

一般來說，您將使用專門為您的語言構建的庫，您嘗試讀取數據的語言是什么？ 許多語言都有一些庫可用，某些語言可能內置支持，如JavaScript。

如果您只是需要了解數據，那么它非常易讀......