為什么 getline 在 switch 中不起作用，而 cin 沒有適當地獲取數據？

Question

我需要了解特定產品適合的汽車型號和年份。 該程序將編寫一個包含文本的文件，該文件將是 html 的輪廓。 我需要將關鍵信息插入正確的位置，以便快速將產品添加到我們的網頁。 當我使用 switch 語句或 if 語句來分隔產品的類別時，輸入會變得混亂並且不允許我回答其中一個問題。 我不能只使用 cin 因為我需要取看起來像“2008 - 2009 - 2010 - 2011”的日期。

這是我到目前為止所得到的！ 這個只是普通的cin ，我試過getline你可以很快 c 我昨天開始，我很新，所以如果這是一個簡單的修復，請原諒我，但我找不到任何東西。

#include <iostream>
#include <string>
#include <fstream>

using namespace std;

void proinfo();

int main()
{
    //Sytem Information
    system("TITLE This is a Beta of My Product Information Template Version 0.0.2");

    //I'm using this as a welcome screen to inform users of new improvements on patches and other pertinent information to the users
    cout << "Welcome To My Product Information Template Maker!!! \n It Is Still In Development" << endl;
    cout << "\n\nworking features are:" << endl << "\t-None\n" << endl;
    system("PAUSE");
    system("CLS");
    proinfo();
}

void proinfo()
{
    //Declare Variables here
    int loop(1), protype;
    char make[256], model[256], year[256];
    string getinput;

    while(loop==1)
    {
        //This is the first menu the user sees where they have to choose what type 
        //of products users will be adding
        system("CLS");
        cout << "Welcome to My Product Information Template Version 0.0.0" << endl;

        cout << "Please select the number of the product" << endl;
        cout << "type you will be ading!\n" << endl;

        cout << "1.Fe - Fe2 Moldings" << endl;
        cout << "2.CF - CF2 Moldings" << endl;

        cout << "What would you like to do? ";

        cin >> protype;

        if(protype==1)
        {
            //FE - FE2 Molding
            system("cls");

            cout << "You have selected" << endl;
            cout << "Fe - Fe2 Moldings\n" << endl;

            cout << "Please Enter the Make of the molding" << endl;
            cin >> make;

            cout << "Please Enter the Model of the molding" << endl;
            cin >> model;

            cout << "Please Enter the Years this molding fits" << endl;
            cin >> year;

            cout << "You have just created a template for a(n)" << year << " " << make << " " << model << endl;
            cout << "Check My Documents For a file called Fe-Fe2template.txt" << endl;

            //Asks to quit or restart
            cout << "Would you like to make another tempalte?" << endl;

            cin >> getinput;

            if(getinput=="yes")
            {
                cout << "Great, Lets keep working!" << endl;
                //End of If statement
            }

            system("PAUSE");
        }

        if(protype==2)  
        {
            //CF - CF2 Molding
            system("cls");

            //Asks to quit or restart
            cout << "Would you like to make another tempalte?" << endl;

            cin >> getinput;

            if(getinput=="yes")
            {
                cout << "Great, Lets keep working!" << endl;
                //End of If statement                   
            }

            system("PAUSE");

            //End of Protype Switch Statement               
        }

        //End of while loop              
    }
    //End of Proinfo()    
}

Answer 1

將年份 [256] 更改為字符串年份；

更改cin>>年； getline(cin, year);

添加行 cin.ignore(); 在getline之前。

您的主要問題是流運算符 >> 將換行符留在流中，因此當您嘗試使用 getline 時，它​​會讀取一個空行。 ignore() 將咀嚼換行符並讓您閱讀您期望的字符串。

所以這應該會讓你上路。

cin.ignore();
cout << "Please Enter the Years this molding fits" << endl;
getline(cin, year);

您還有一些其他小問題，但您會解決的。 最糟糕的是忘記終止循環。

if(getinput=="yes")
{
    cout << "Great, Lets keep working!" << endl;
   //End of If statement
}
else
{
    loop = 0;
    continue;
}