Apache POI XSSF 讀取 excel 文件

Question

我只是有一個關於如何使用 Apache 的 XSSF 格式讀取 xlsx 文件的快速問題。

現在我的代碼是這樣的：

InputStream fs = new FileInputStream(filename);   // (1)
XSSFWorkbook wb = new XSSFWorkbook(fs);           // (2)
XSSFSheet sheet = wb.getSheetAt(0);               // (3)

...導入了所有相關的東西。 我的問題是，當我點擊運行時，它卡在第 (2) 行，幾乎是無限循環。 filename只是一個字符串。

如果有人能給我一些關於如何解決這個問題的示例代碼，我將不勝感激。 我現在想要的只是從 xlsx 文件中讀取單個單元格； 我對 xls 文件使用 HSSF，沒有任何問題。

謝謝你的幫助，安德魯

Answer 1

InputStream inp = null;
        try {
            inp = new FileInputStream("E:/sample_poi.xls");

            Workbook wb = WorkbookFactory.create(inp);
            Sheet sheet = wb.getSheetAt(0);
            Header header = sheet.getHeader();

            int rowsCount = sheet.getLastRowNum();
            System.out.println("Total Number of Rows: " + (rowsCount + 1));
            for (int i = 0; i <= rowsCount; i++) {
                Row row = sheet.getRow(i);
                int colCounts = row.getLastCellNum();
                System.out.println("Total Number of Cols: " + colCounts);
                for (int j = 0; j < colCounts; j++) {
                    Cell cell = row.getCell(j);
                    System.out.println("[" + i + "," + j + "]=" + cell.getStringCellValue());
                }
            }

        } catch (Exception ex) {
            java.util.logging.Logger.getLogger(FieldController.class.getName()).log(Level.SEVERE, null, ex);
        } finally {
            try {
                inp.close();
            } catch (IOException ex) {
                java.util.logging.Logger.getLogger(FieldController.class.getName()).log(Level.SEVERE, null, ex);
            }
        }

Answer 2

我相信這會回答你的問題： http ://poi.apache.org/spreadsheet/quick-guide.html#ReadWriteWorkbook

簡而言之，您的代碼應如下所示：

InputStream inp = new FileInputStream("workbook.xlsx");
Workbook wb = WorkbookFactory.create(inp);
Sheet sheet = wb.getSheetAt(0);
Row row = sheet.getRow(2);
Cell cell = row.getCell(3);

Answer 3

為什么要將文件分解為 InputStream？ XSSFWorkbook 有一個構造函數，它只是將路徑作為字符串。 只需對字符串的路徑進行硬編碼。創建工作簿后，您可以從中創建 XSSFSheets。 然后是 XSSFCells，它最終將允許您讀取單個單元格的內容（單元格基本上基於 x,y 位置）

Answer 4

您可以嘗試以下操作。

private static void readXLSX(String path) throws IOException {
    File myFile = new File(path);
    FileInputStream fis = new FileInputStream(myFile);

    // Finds the workbook instance for XLSX file
    XSSFWorkbook myWorkBook = new XSSFWorkbook (fis);

    // Return first sheet from the XLSX workbook
    XSSFSheet mySheet = myWorkBook.getSheetAt(0);

    // Get iterator to all the rows in current sheet
    Iterator<Row> rowIterator = mySheet.iterator();

    // Traversing over each row of XLSX file
    while (rowIterator.hasNext()) {
        Row row = rowIterator.next();

        // For each row, iterate through each columns
        Iterator<Cell> cellIterator = row.cellIterator();
        while (cellIterator.hasNext()) {

            Cell cell = cellIterator.next();

            switch (cell.getCellType()) {
            case Cell.CELL_TYPE_STRING:
                System.out.print(cell.getStringCellValue() + "\t");
                break;
            case Cell.CELL_TYPE_NUMERIC:
                System.out.print(cell.getNumericCellValue() + "\t");
                break;
            case Cell.CELL_TYPE_BOOLEAN:
                System.out.print(cell.getBooleanCellValue() + "\t");
                break;
            default :

            }
        }
        System.out.println("");
    }
}

Answer 5

這很好用：試試吧

File filename = new File("E:/Test.xlsx");
FileInputStream isr= new FileInputStream(filename);

Workbook book1 = new XSSFWorkbook(isr);
Sheet sheet = book1.getSheetAt(0);  
Iterator<Row> rowItr = sheet.rowIterator();

Answer 6

public class ExcelReader{
   public String path;
   public static FileInputStream fis;

   public ExcelReader(){
      System.out.println("hello");
   }

   public ExcelReader(String path){
      this.path=path;
      fis=new FileInputStream(path);
      XSSFWorkbook workbook=new XSSFWorkbook(fis);
      XSSFSheet sheet=workbook.getSheet("Sheet1");//name of the sheet
      System.out.println(sheet.getSheetName());
      System.out.println(sheet.getLastRowNum());
      System.out.println(sheet.getRow(2).getCell(3));
  }
  public static void main(String[] args) throws IOException {
      ExcelReader excel=new ExcelReader("path of xlsx");
  }
}

Answer 7

我有同樣的錯誤，我剛剛用相同的版本更新了 pom 依賴項。 有效。

        <!-- https://mvnrepository.com/artifact/org.apache.poi/poi -->
        <dependency>
            <groupId>org.apache.poi</groupId>
            <artifactId>poi</artifactId>
            <version>4.1.0</version>
        </dependency>
        <!-- https://mvnrepository.com/artifact/org.apache.poi/poi-ooxml -->
        <dependency>
            <groupId>org.apache.poi</groupId>
            <artifactId>poi-ooxml</artifactId>
            <version>4.1.0</version>
        </dependency>

Answer 8

// Load sheet- Here we are loading first sheet only
XSSFSheet xlSheet = wb.getSheetAt(0);

這里的代碼僅識別第一張工作表 - 在我的 Excel 中，有多張工作表存在因此面臨將sheet2更改為sheet1(getSheetAt(0)) ...