[英]javascript: how to find the key in an associative array that is closest to a value?
[英]javascript find value from array based on associative array key value
我有一個關聯數組:
var array1 = {
a1: {
id: "box1",
title: "box 1"
},
a2: {
id: "box2",
title: "box 2"
},
a3: {
id: "box3",
title: "box 3"
}
};
然后,我還有另一個引用第一個數組的數組:
var array_order = ["a3:positionA", "a2:postitionB", "a1:positionC"];
我想遍歷第一個列表,然后使用第二個列表查找位置文本
我正在使用jQuery,所以我有
$.each(array1, function(i,o) {
something in here where I can use i to find out what position. e.g. if a1 I would get positionC
}
在array_order
而不是array1
更輕松,更快速地進行迭代:
for( var i = 0, len = array_order.length; i < len; i++ ) {
var ref = array_order[i].split(':');
if( ref.length === 2 && ({}).hasOwnProperty.call( array1, ref[0] ) ) {
var array1Property = array1[ ref[0] ];
var array1PropertyPosition = ref[1];
}
}
也可以實現對array1
屬性的迭代,但是它要慢得多:
for( var prop in array1 )
if( ({}).hasOwnProperty.call( array1, prop ) )
for( var i = 0, len = array_order.length; i < len; i++ ) {
var ref = array_order[i].split(':');
if( ref.length === 2 && prop === ref[1] ) {
var array1Property = array1[ prop ];
var array1PropertyPosition = ref[1];
}
}
而且jQuery中沒有必要。
好的,首先,JS只將關聯數組稱為對象。
遍歷對象中的每個鍵
for(var prop in array1) {
if(array1.hasOwnProperty(prop))
for(key in array_order){
if( key === prop){
doSomethingwith(array_order[key]);
}
}
}
var temp_array_order = {};
$.each(array_order, function(key, val) {
temp_array_order[val.substr(0,2)] = val.substr(3);
};
$.each(array1, function(key, val) {
var category = temp_array_order[key];
...
});
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