[英]Select last record from same day
繼承人的問題...我有一個循環,就像這樣從我的數據庫中選擇東西。
$query = "SELECT * FROM table WHERE publish <= CURDATE() AND active = 'Yes' AND (YEAR(begin) = YEAR(CURDATE()) OR YEAR(begin) = YEAR(CURDATE()) + 1) ORDER BY begin ASC";
$resultSet = mysql_query($query);
if (mysql_num_rows($resultSet))
{
$newsArray = array();
while ($newsResult = mysql_fetch_array($resultSet))
{
$newDate = $newsResult['begin'] ;
$timePeriod = date('F Y ',strtotime($newDate));
$timePeriodY = date('Y',strtotime($timePeriod));
$timePeriodM = date('F',strtotime($timePeriod));
if (!isset($newsArray[$timePeriod]))
{
$newsArray[$timePeriod] = array();
}
$newsArray[$timePeriod][] = $newsResult;
}
foreach ($newsArray as $timePeriod => $newsItems)
{
$timePeriodY = date('Y',strtotime($timePeriod));
if ($timePeriodY == $thisYear){
}
else if ($timePeriodY == $nextYear){
}
echo '<h2 class="year>'.$timePeriodY.'</h2>';
echo '<ul class="column">';
foreach ($newsArray as $timePeriod => $newsItems)
{
$timePeriodMonth = date('Y',strtotime($timePeriod));
if ($timePeriodY == $timePeriodMonth) {
$moSe = strftime('%B',strtotime($timePeriod));
$MonthSe = ucfirst($moSe);
$seMonth = str_replace($dateSearch,$dateReplace,date('F',strtotime($timePeriod)));
echo $seMonth;
foreach ($newsItems as $item)
{
$ad_event = date("Y-m-d",strtotime($item['event_end']));
$today = date("Y-m-d");
$dayMod = strftime('%e',strtotime($item['event_begin']));
$seDay = str_replace($dateSearch,$dateReplace,date('D',strtotime($item['event_begin'])));
echo '<a href="javascript:gotoDotBottom('.$item['event_id'].',\''.$item['event_url'].'\');" id="e'.$item['event_id'].'" class="eventLink '.$markedEvent.'" overhead="'.$item['event_title'].'" overdate="'.date("Y-m-d",strtotime($item['event_begin'])).'" overtext="'. strip_tags($showSum) .'">'.$seDay.' '.$dayMod.' - '.$item['event_title'].'</a>';
echo '</div>';
}
}
}
}
}
else
{
echo '';
}
此代碼輸出每一行的數據,並將其分隔為年月日等。但是,某些數據在同一天。 很好,但是當數據在同一天時,我想要一個變量,該變量僅保留同一天的最后一項。
例如
D B
PUBLISH ID NAME
2011-05-05 1 test 1
2011-05-05 2 test 2
2011-05-06 3 test 3
我想要的結果是這樣的
結果
test 1 ID 1 PUBLISH 2011-05-05 VARIABLE 2 <<-- see the variable that comes from test 2 row
test 2 ID 2 PUBLISH 2011-05-05 VARIABLE 2
test 3 ID 3 PUBLISH 2011-05-06 VARIABLE 3
在這種情況下,測試1包含測試2的信息,因為測試2在測試1之后,並且兩者的日期相同。 如果在特定日期只有一個,如測試2和3,則回顯與變量相同的ID。
有任何想法嗎? 請告訴我是否需要進一步解釋一下:)
非常感謝您的幫助!
按日期(開始)分組,因為您只希望同一日期(開始)上有1條記錄,並且由於您希望按dsc在“開始”列上進行最新排序(我相信“開始”存儲為日期時間,否則您需要使用dsc在table.ID上)
$query = "SELECT *
FROM table
WHERE publish <= CURDATE()
AND active = 'Yes'
AND (YEAR(begin) = YEAR(CURDATE())
OR YEAR(begin) = YEAR(CURDATE()) + 1)
GROUP BY begin
ORDER BY begin DSC";
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.