有沒有比使用自定義案例語句更實用的方法來在 Ruby 中編寫這個？

Question

想象一下下面的代碼：

class SimpleLetter
  def values
    ("a" .. "z").to_a
  end

  def ===(other)
    values.include?(other)
  end
end

class Vowel < SimpleLetter
  def values
    ["a","e","i","o","u"]
  end
end

class Consonant < SimpleLetter
  def values
    super - Vowel.new.values
  end
end

objects = ("a" .. "f").to_a + (1 .. 5).to_a

objects.each do |letter|
  case letter
    when Vowel.new
      puts "#{letter} it's a vowel"
    when Consonant.new
      puts "#{letter} it's a consonant"
    else
      puts "#{letter} it's something else"
  end
end

我本可以選擇任何其他類，我只是以它們為例。 我非常喜歡 Scala 的match和提取器，我認為這可能是在 Ruby 中編寫相同內容的好方法。 有沒有更好的方法來編寫上面的內容而不必實例化新對象，這樣我就可以調用他們的===方法？

只是為了避免不必要的帖子，是的，我知道我可以這樣做：

case letter
  when ["a","e","i","o","u"].include?(letter)
    # ...
end

Answer 1

你不需要角色的類。 將它們設置為 arrays，並在 case 語句中使用 splat 運算符。

SimpleLetter = ("a" .. "z").to_a
Vowel        = %w[a e i o u]
Consonant    = SimpleLetter - Vowel

(("a" .. "f").to_a + (1 .. 5).to_a).each do |letter|
  case letter
    when *Vowel
      puts "#{letter} it's a vowel"
    when *Consonant
      puts "#{letter} it's a consonant"
    else
      puts "#{letter} it's something else"
  end
end

Answer 2

===也適用於塊：

Letters = ('a'..'z').to_a
Vowels = ['a','e','i','o','u']
Consonants = Letters - Vowels

Vowel = lambda { |x| Vowels.include? x }
Consonant = lambda { |x| Consonants.include? x }

objects = ("a" .. "f").to_a + (1 .. 5).to_a

objects.each do |object|
  case object
    when Vowel
      puts "#{object} is a vowel."
    when Consonant
      puts "#{object} is a consonant."
    else
      puts "#{object} is an object."
  end
end

Answer 3

您可以使用 class 方法而不是實例方法：

class SimpleLetter
    def self.values
        ("a" .. "z").to_a
    end 

    def self.===(other)
        values.include?(other)
    end 
end

class Vowel < SimpleLetter
    def self.values
        ["a","e","i","o","u"]
    end 
end

class Consonant < SimpleLetter
    def self.values
        super - Vowel.values
    end 
end

objects = ("a" .. "f").to_a + (1 .. 5).to_a

objects.each do |letter|

    case letter
        when Vowel
            puts "#{letter} it's a vowel"
        when Consonant
            puts "#{letter} it's a consonant"
        else
            puts "#{letter} it's something else"
    end 

end

Answer 4

您讓我感到困惑的代碼，因為SimpleLetter應該是單個字母，而不是整個字母表。

盡管猴子補丁有點冒險，但我很想做以下事情：

module Voweliness
  def vowel?
    self =~ /[aeiou]/i
  end

  def consonant?
    (self =~ /[a-z]/i and not vowel?)
  end
end

class String
  include Voweliness
end


objects.each do |letter|
  case
    when letter.vowel?
      puts "#{letter} is a vowel"
    when letter.consonant?
      puts "#{letter} is a consonant"
    else
      puts "#{letter} is something else"
  end
end

Answer 5

你已經有幾個很好的答案（例如sawa's），所以我包括一個只是為了好玩而沒有case陳述的答案：

SIMPLE_LETTER = [*"a" .. "z"]
VOWEL        = %w[a e i o u]
CONSONANT    = SIMPLE_LETTER - VOWEL

[*?a..?f,*1..5].each do |letter|
  letter_class = %w(vowel consonant).select { |c| Object.const_get(c.upcase).include? letter}.first
  puts "'#{letter}': #{ letter_class || "something else"}"
end

Output：

'a': vowel
'b': consonant
'c': consonant
'd': consonant
'e': vowel
'f': consonant
'1': something else
'2': something else
'3': something else
'4': something else
'5': something else

multi-splat 和字符文字僅在 1.9 中有效。