[英]compare list elements
如何將一個元素與排序列表中的下一個元素進行比較,並打印出它們的差異。 任何幫助,將不勝感激。
Eg:
lst = [3.18,10.57,14.95,...]
10.57 - 3.18 = 7.39
14.95 - 10.57 = 4.38
...
it = iter(lst)
it.next()
print [(x, y, y - x) for (x, y) in itertools.izip(lst, it)]
如果您正在處理數值數據,請考慮使用 numpy
import numpy as np
lst = [3.18,10.57,14.95]
arr = np.array(lst)
diff = np.diff(arr)
>>> diff
array([ 7.39, 4.38])
如果必須,您可以將其轉換回列表:
diff_list = list(diff)
否則,您可以像遍歷列表一樣遍歷它:
for item in diff:
print(item)
7.39
4.38
編輯:我計時的五個解決方案彼此非常接近,所以選擇一個更容易閱讀的解決方案
t = timeit.Timer("[b - a for a, b in zip(l, l[1:])]", "l = range(int(1e6))")
print(t.timeit(1))
>>> 0.523894071579
t = timeit.Timer("list(np.diff(np.array(l)))", "import numpy as np; l = range(int(1e6))")
print(t.timeit(1))
>>> 0.484916915894
t = timeit.Timer("diffs = [l[x + 1] - l[x] for x in range(len(l) - 1)]", "l = range(int(1e6))")
print(t.timeit(1))
>>> 0.363043069839
t = timeit.Timer("[(x, y, y - x) for (x, y) in itertools.izip(l, it)]", "l = range(int(1e6)); it = iter(l); it.next()")
print(t.timeit(1))
>>> 0.54354596138
# pairwise solution
t = timeit.Timer("a, b = itertools.tee(l); next(b, None); [(x, y) for x, y in itertools.izip(a, b)]", "l = range(int(1e6));")
print(t.timeit(1))
>>> 0.477301120758
diffs = [lst[x + 1] - lst[x] for x in range(len(lst) - 1)]
for x in diffs:
print x
使用zip
和 zip 列表與自身。
l = [1, 2, 4, 7]
[b - a for a, b in zip(l, l[1:])]
# [1, 2, 3]
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