簡體   English   中英

Null 指針異常未在 java 對話中捕獲

[英]Null Pointer Exception not caught in java dialogue

我正在嘗試從 java 對話框接收輸入,並且在關閉框時我似乎無法捕獲NullPointerException ,有人可以幫忙嗎?

private static final String DEFAULTNAME = "Player001"; 

public class Player implements Serializable
{
    private String name;
    private int score;

    public Player(String Pname,int Pscore)
    {
         name = Pname;
         score = Pscore;
    }
}

    try
    {
        person = new Player(JOptionPane.showInputDialog("Please enter your name"),0);
    }
    catch(NullPointerException e)
    {
        person = new Player(DEFAULTNAME,0);
    }
    catch(Throwable t)
    {
        person = new Player(DEFAULTNAME,0);
    }

有沒有人有解決方案或者有沒有辦法讓對話框無法關閉?

你不會像你正在做的那樣“抓住”一個 NPE。 從用戶那里獲取String,看是否== null,如果是則使用默認播放器名稱。 在偽代碼中:

call JOptionPane and get player name
If player name is null
  create new Player with default name
else
  create new Player with the user-entered name.

這里不需要嘗試/捕獲。

另一種解決方法是讓您的 Player 構造函數接受 null 字符串並將其更改為默認值:

public Player(String Pname,int Pscore)
{
     name = (Pname == null || Pname.trim().isEmpty()) ? DEFAULT_NAME : Pname;
     score = Pscore;
}

您最好在添加之前檢查名稱中的無效值

String name = JOptionPane.showInputDialog("Please enter your name");
if(name == null || name.equals(""))name = DEFAULTNAME;
person = new Player(name,0);

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM