[英]Can you use multiple conditionals in SASS/SCSS CSS
我正在使用 SCSS 代碼來設置我的 ruby 應用程序的樣式,並且正在嘗試編寫自己的“圓角”mixin 來幫助解決多瀏覽器邊框的圓角問題。
目前我有以下內容:
@mixin rounded($corner: all , $radius: 8px) {
@if $corner==all || $corner==bottom || $corner == right || $corner==bottom-right{webkit-border-bottom-right-radius: $radius;}
@if $corner==all || $corner==bottom || $corner == left || $corner==bottom-left{-webkit-border-bottom-left-radius: $radius;}
@if $corner==all || $corner==top || $corner == right || $corner==top-right{-webkit-border-top-right-radius: $radius;}
@if $corner==all || $corner==bottom || $corner == left || $corner==top-left{-webkit-border-top-left-radius: $radius;}
@if $corner==all || $corner==bottom || $corner == right || $corner==bottom-right{-khtml-border-radius-bottomright: $radius;}
@if $corner==all || $corner==bottom || $corner == left || $corner==bottom-left{-khtml-border-radius-bottomleft: $radius;}
@if $corner==all || $corner==top || $corner == right || $corner==top-right{-khtml-border-radius-topright: $radius;}
@if $corner==all || $corner==bottom || $corner == left || $corner==top-left{-khtml-border-radius-topleft: $radius;}
@if $corner==all || $corner==bottom || $corner == right || $corner==bottom-right{-moz-border-radius-bottomright: $radius;}
@if $corner==all || $corner==bottom || $corner == left || $corner==bottom-left{-moz-border-radius-bottomleft: $radius;}
@if $corner==all || $corner==top || $corner == right || $corner==top-right{-moz-border-radius-topright: $radius;}
@if $corner==all || $corner==bottom || $corner == left || $corner==top-left{-moz-border-radius-topleft: $radius;}
@if $corner==all || $corner==bottom || $corner == right || $corner==bottom-right{border-bottom-right-radius: $radius;}
@if $corner==all || $corner==bottom || $corner == left || $corner==bottom-left{border-bottom-left-radius: $radius;}
@if $corner==all || $corner==top || $corner == right || $corner==top-right{border-top-right-radius: $radius;}
@if $corner==all || $corner==bottom || $corner == left || $corner==top-left{border-top-left-radius: $radius;}
}
但是,似乎 SASS 只能處理 if 語句中的一個條件? 有沒有辦法解決這個問題,還是我必須為每個圓角做四個 if 語句?
我是這樣寫的:希望你會發現它有用。
@mixin rounded($amount: "10px",$position: null) {
@if $position != null {
@if $position == "top" or $position == "bottom" {
// top or bottom
-webkit-border#{$position}-left-radius: $amount;
-moz-border#{$position}-left-radius: $amount;
border#{$position}-left-radius: $amount;
-webkit-border#{$position}-right-radius: $amount;
-moz-border#{$position}-right-radius: $amount;
border#{$position}-right-radius: $amount;
} @else {
// top-left or top-right or bottom-left or bottom-right
-webkit-border#{$position}-radius: $amount;
-moz-border#{$position}-radius: $amount;
border#{$position}-radius: $amount;
}
} @else {
// ALL IF EMPTY
-webkit-border-radius: $amount;
-moz-border-radius: $amount;
border-radius: $amount;
}
}
你像這樣使用它:
@include rounded(); /*as default 10px on all corners*/
@include rounded(15px); /*all corners*/
@include rounded(15px, top); /*all top corners*/
@include rounded(15px, bottom); /* all bottom corners*/
@include rounded(15px, top-right); /*this corner only*/
@include rounded(15px, top-left); /*this corner only*/
@include rounded(15px, bottom-right); /*this corner only*/
@include rounded(15px, bottom-left); /*this corner only*/
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.