[英]Symfony Functional Test JSON
如果操作返回 json object,我如何測試 Symfony 功能測試中的響應?
我有代碼
with('response')->begin()-> isHeader('content-type','application/json')-> end() ;
但測試總是失敗。
下面的 URL 可能會告訴你如何測試它:實用 symfony 第 15 天: Web 服務
以下是該頁面的相關代碼:
$browser->
info('1 - Web service security')->
info(' 1.1 - A token is needed to access the service')->
get('/api/foo/jobs.xml')->
with('response')->isStatusCode(404)->
info(' 1.2 - An inactive account cannot access the web service')->
get('/api/symfony/jobs.xml')->
with('response')->isStatusCode(404)->
info('2 - The jobs returned are limited to the categories configured for the affiliate')->
get('/api/sensio_labs/jobs.xml')->
with('request')->isFormat('xml')->
with('response')->begin()->
isValid()->
checkElement('job', 32)->
end()->
info('3 - The web service supports the JSON format')->
get('/api/sensio_labs/jobs.json')->
with('request')->isFormat('json')->
with('response')->matches('/"category"\: "Programming"/')->
info('4 - The web service supports the YAML format')->
get('/api/sensio_labs/jobs.yaml')->
with('response')->begin()->
isHeader('content-type', 'text/yaml; charset=utf-8')->
matches('/category\: Programming/')->
end()
;
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