[英]how does istringstream operator>> return value work?
此示例讀取具有 integer、運算符和另一個 integer 的行。 例如,
// sstream-line-input.cpp - Example of input string stream.
// This accepts only lines with an int, a char, and an int.
// Fred Swartz 11 Aug 2003
#include <iostream>
#include <sstream>
#include <string>
using namespace std;
//================================================================ main
int main() {
string s; // Where to store each line.
int a, b; // Somewhere to put the ints.
char op; // Where to save the char (an operator)
istringstream instream; // Declare an input string stream
while (getline(cin, s)) { // Reads line into s
instream.clear(); // Reset from possible previous errors.
instream.str(s); // Use s as source of input.
if (instream >> a >> op >> b) {
instream >> ws; // Skip white space, if any.
if (instream.eof()) { // true if we're at end of string.
cout << "OK." << endl;
} else {
cout << "BAD. Too much on the line." << endl;
}
} else {
cout << "BAD: Didn't find the three items." << endl;
}
}
return 0;
}
operator>>
返回 object 本身 (*this)。
測試if (instream >> a >> op >> b)
如何工作的?
我認為測試總是true
,因為instream!=NULL
。
basic_ios
class (它是istream
和ostream
的基礎)具有到void*
的轉換運算符,可以隱式轉換為bool
。 這就是它的工作原理。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.