[英]C Pointer to Pointer and Pass by Reference
我正在嘗試學習 C,我對指針的指針有點掛斷。 我想我理解你為什么需要它們,但不能完全理解正在發生的事情。
例如,下面的代碼似乎不像我期望的那樣工作:
#include <stdio.h>
int newp(char **p) {
char d = 'b';
*p = &d;
/*printf("**p = %c\n", **p);*/
return 1;
}
int main() {
char c = 'a';
char *p = &c;
int result;
result = newp(&p);
printf("result = %d\n", result);
printf("*p = %c\n", *p);
printf("c = %c\n", c);
return 0;
}
我得到的結果是這樣的:
result = 1
*p =
c = a
*p 打印為空。 相反,我希望*p = b
。
但是,如果我取消注釋第 6 行( newp
函數中的printf
),那么我會得到:
**p = b
result = 1
*p = b
c = a
我錯過了什么?
您正在處理未定義的行為。 變量d
是本地的(駐留在堆棧上)並且在封閉的 function ( newp
) 返回后不可用。
當在newp
之外取消引用p
時,堆棧&d
上的地址可能會被其他一些局部變量覆蓋,或者它可能包含垃圾。
您將局部變量 ( d
) 的地址存儲在*p
中,然后在變量超出 scope 時取消引用它。 未定義的行為
您可能“缺少”關鍵字static
,如:
int newp(char **p) {
static char d = 'b'; /* <--- HERE */
*p = &d;
/*printf("**p = %c\n", **p);*/
return 1;
}
這個static
關鍵字使編譯器將局部變量定位在“靜態存儲”中,該局部變量在調用newp()
之后的時間段內繼續存在(即保持其值)。 但是,此 memory 只有一個副本 - 包含 function ( newp
) 的每個后續調用都重新使用相同的 memory 位置並可能覆蓋當時的值。
如果沒有static
關鍵字來限定您的局部變量聲明,則存儲將是“自動”的,這意味着在包含 function 已返回后,它將自動從當前使用中解除。 newp
返回后,以前用於局部變量的 memory 可以用於任何目的。
#include <stdio.h>
// Here *pointer means that the parameter that this function
// will expect will be a pointer.
void changeViaPointer(int *pointer);
// Pointer of a pointer.
void changeViaPointerInBetween(int **pointer);
int main(){
int number;
number = 20;
// Here *pointer means that the variable that is declared will be a pointer.
int *pointer;
// Actually asigning value to the pointer variable.
pointer = &number;
// Pointer of a pointer.
int **pointerInBetween;
// Assigning value to the pointer of a pointer.
// Assigning the memory location where this pointer points to.
// So this is a pointer in between.
pointerInBetween = &pointer;
printf("The number before changing is %d\n", number);
// Pass the pointer variable.
changeViaPointer(pointer);
printf("The number after pointer changing is %d\n", number);
// Pass the pointer of a pointer variable.
changeViaPointerInBetween(pointerInBetween);
printf("The number after pointer in between changing is %d\n", number);
return 0;
}
void changeViaPointer(int *pointer){
// Okay, at this point we have received a variable called pointer,
// which points to some value. In order to access this value
// we need to use *pointer.
// BUT THIS IS DIFFERENT FROM THE *pointer IN THE FUNCTION DECLARATION!!!
*pointer = *pointer + 20;
}
void changeViaPointerInBetween(int **pointer){
// **pointer explanation:
// Only pointer is the memory location
// *pointer is the value of that memory location, which in this specific case is also a memory location
// **pointer is the value of what the other pointer points to.
**pointer = **pointer + 20;
}
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