T-SQL：按年、月排序結果

Question

我有以下聲明：

select
    (datename(MM, SomeDate) + ' ' + datename(day, SomeDate)) as D,
    count(SomeID) as IDs
from dbo.SomeTable
where
    datename(MM, SomeDate) = @Month
    and datename(YYYY, SomeDate) = @Year
group by
    datename(YYYY, SomeDate),
    datename(MM, SomeDate),
    datename(DD, SomeDate);

它有效，但它對結果進行排序，如下所示：

July 1, 2011 - 2
July 10, 2011 - 4
July 2, 2011 - 10

如何讓它在 7 月 2 日之后顯示 7 月 10 日？ 我知道這很簡單，但我找不到問題。 謝謝你的幫助！

編輯：伙計們，我知道必須有一個“訂單”，我認為這很明顯。 但是“正常”排序會產生相同的結果（請參閱我的評論）。 我認為這與整理有關，但我不是那里的專家。

Answer 1

設法通過將查詢主體移動到子查詢中來修復它，包括 Group by 子句中的SomeDate （確保刪除時間部分）。

我個人會避免在此查詢中使用DateName - 我寧願使用DatePart並保留所有數字，但基於您的查詢：

設置：

create table SomeTable (
    SomeDate datetime not null,
    SomeID int not null
)
go
insert into SomeTable (SomeDate,SomeID)
select '20110701',1 union all
select '20110702',1 union all
select '20110710',1

詢問：

declare @Month varchar(10)
declare @Year int
select @Month='July',@Year=2011

select D,IDs from (
select
    (datename(MM, SomeDate) + ' ' + datename(day, SomeDate)) as D,
    count(SomeID) as IDs
    ,DATEADD(day,DATEDIFF(day,0,SomeDate),0) as SomeDate
from dbo.SomeTable
where
    datename(MM, SomeDate) = @Month
    and datename(YYYY, SomeDate) = @Year
group by
    datename(YYYY, SomeDate),
    datename(MM, SomeDate),
    datename(DD, SomeDate),
    DATEADD(day,DATEDIFF(day,0,SomeDate),0)
) t
order by SomeDate

Answer 2

如果SomeDate是DATE類型，那么您可以簡單地添加ORDER BY SomeDate 。 GROUP BY也可以簡化：

select
    (datename(MM, SomeDate) + ' ' + datename(day, SomeDate)) as D,
    count(SomeID) as IDs
from dbo.SomeTable
where
    datename(MM, SomeDate) = @Month
    and datename(YYYY, SomeDate) = @Year
group by
    SomeDate 
order by
    SomeDate ;

WHERE也可以簡化。

---

如果它是DATETIME類型，您可以使用：

select
    (datename(MM, DATEADD(dd, 0, DATEDIFF(dd, 0, SomeDate)))
      + ' ' + datename(day, DATEADD(dd, 0, DATEDIFF(dd, 0, SomeDate)))) as D,
    count(SomeID) as IDs
from dbo.SomeTable
where
    datename(MM, SomeDate) = @Month
    and datename(YYYY, SomeDate) = @Year
group by
    DATEADD(dd, 0, DATEDIFF(dd, 0, SomeDate)) 
order by
    DATEADD(dd, 0, DATEDIFF(dd, 0, SomeDate)) ;

Answer 3

您正在丟失somedate的信息，並且無論如何都不能用於 ORDER BY

按 DATENAME 排序不是您想要的，因為 7 月在 8 月之后

因此，將更多派生列添加到 GROUP BY 以便稍后使用 DATEPART 進行排序，它給出數字

select
    (datename(MM, SomeDate) + ' ' + datename(day, SomeDate)) as D,
    count(SomeID) as IDs
from
    dbo.SomeTable
where
    datename(MM, SomeDate) = @Month
    and datename(YYYY, SomeDate) = @Year
group by
    datename(YYYY, SomeDate),
    datename(MM, SomeDate),
    datename(DD, SomeDate),
    datepart(YYYY, SomeDate),
    datepart(MM, SomeDate),
    datepart(DD, SomeDate)
order by
    datepart(YYYY, SomeDate),
    datepart(MM, SomeDate),
    datepart(DD, SomeDate)

Answer 4

您需要添加一個ORDER BY子句並按SomeDate 。

Answer 5

SELECT COUNT(*)
   /*Event_type
   EventDate*/ AS EventCount
  ,MONTH(EventDate) AS MONTH
  ,YEAR(EventDate) AS YEAR
  ,DATENAME(MONTH ,EventDate) AS MonthName
FROM   EventTable
WHERE  (Event_type = 'TypeOfEvent')
   AND (Userid NOT LIKE '%*%')
GROUP BY
   YEAR(EventDate)
  ,MONTH(EventDate)
  ,DATENAME(MONTH ,EventDate)
ORDER BY
   YEAR
  ,MONTH