php 比較字符串的關鍵字

Question

我需要將這兩個關鍵字字符串與 php 進行比較。

$original_keywords = cat, dog, mouse

$possible_keywords_1 = "cat, dog, hamster";       
$possible_keywords_2 = "cat, sheep, goat"; 

我需要一個 php 腳本來將數值“1”分配給第一個可能的字符串（1 個匹配項），將“2”分配給第二個可能的字符串（2 個匹配項）。 誰能幫幫我？

Answer 1

$original_keywords = array("cat", "dog", "mouse");
$possible_keywords1 = preg_split('/,\s*/', "cat, dog, hamster");
echo count(array_intersect($original_keywords, $possible_keywords1))

Answer 2

$original_keywords = "cat, dog, mouse";
$possible_keywords_1 = "cat, dog, hamster";
$possible_keywords_2 = "cat, sheep, goat";

// Put the input keywords into an array
$keywords = explode(', ', $original_keywords);

// Put all incoming keywords into one big array (you can add as many arrays
// as you want here)
$input = array_merge(
    explode(', ', $possible_keywords_1),
    explode(', ', $possible_keywords_2));

// Count how many times each keywords from $input appears
$count = array_count_values($input);

// Filter out from $count any keyword that is not present in $keywords
$result = array_intersect_key($count, array_flip($keywords));

看到它在行動。

Answer 3

您可以結合使用explode和array_intersect來做到這一點

以下是開始的代碼：

$possible_keywords_1_array = explode(",", $possible_keywords_1); 
$possible_keywords_2_array = explode(",", $possible_keywords_2); 
$matches = count(array_intersect($possible_keywords_1_array, $possible_keywords_2_array));