以日期的年、月、日分隔

Question

如何區分年、月、日。 並且每個都放入變量？

1390/02/05
$year = '1390';
$month = '02';
$day = '05';

尊重地

Answer 1

就像是：

list($year, $month, $day) = explode('/', '1390/02/05', 3);

Answer 2

$timestamp = strtotime('1390/02/05');
$year = date('Y', $timestamp);
$month = date('m', $timestamp);
$day = date('d', $timestamp);

Answer 3

你可以這樣做：

$date = '1390/02/05';
$array = $explode('/', $date);

$year = $array[0];
$month = $array[1];
$day = $array[2];

Answer 4

list($year, $month, $day) = explode('/', '1390/02/09', 3);