[英]Find and show the route of the closest markers using DirectionsService by Google Map API v3
[英]Google maps api v2 - find closest/nearest markers/points in the map ?
嗨,我正在嘗試做似乎幾乎不可能的事情……我正在嘗試獲取三個最近的位置標記對象……這甚至可能嗎? ..它不一定是100%准確的...但是至少要做一些...我在網上發現並嘗試過的操作是:
function find_closest_marker( lat1, lon1 ) {
for(var y = 1; y < 4; y++){
var pi = Math.PI;
var R = 6371; //equatorial radius
for(var i=0;i<markers.length; i++ ) {
//alert(markers.length);
var closest = -1;
var distances = [];
var lat2 = points[i].lat().toFixed(5);
var lon2 = points[i].lng().toFixed(5);
var chLat = lat2-lat1;
var chLon = lon2-lon1;
var dLat = chLat*(pi/180);
var dLon = chLon*(pi/180);
var rLat1 = lat1*(pi/180);
var rLat2 = lat2*(pi/180);
var a = Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.sin(dLon/2) * Math.sin(dLon/2) * Math.cos(rLat1) * Math.cos(rLat2);
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c;
distances[i] = d;
if ( closest == -1 || d < distances[closest] ) {
closest = i;
}
}
var markerImg = "";
if(markers[closest].markerType == 1){
markerImg="/files/billeder/../Templates/Designs/Ideal2011/images/Map/dot_red.jpg"
} else if(markers[closest].markerType == 2){
markerImg="/files/billeder/../Templates/Designs/Ideal2011/images/Map/dot_lblue.jpg"
}else if(markers[closest].markerType == 3){
markerImg="/files/billeder/../Templates/Designs/Ideal2011/images/Map/dot_dblue.jpg"
}else if(markers[closest].markerType == 4){
markerImg="/files/billeder/../Templates/Designs/Ideal2011/images/Map/dot_green.jpg"
}
$('.nearestPlace'+y).html(
"<img src='"+markerImg+"' alt='"+markers[closest].address+"' />"+
"<div class='CompanyName'><strong>"+markers[closest].title+"</strong></div>"+
markers[closest].address+"<br/>"+
markers[closest].postby+"<br/>"+
"Tlf.: "+markers[closest].phone+"<br/>"+
markers[closest].fax+
markers[closest].web+
markers[closest].email
);
//markers.pop(markers[closest]);
//points.pop(points[closest]);
//markers[closest] = "";
//points[closest]= "";
//alert(closest);
//markers.slice(closest,closest+1);
//points.slice(closest,closest+1);
//alert(markers[closest].title)
delete markers[closest];
delete points[closest]
}
}
您如何從代碼中的一些注釋中看到我嘗試了許多不同的東西! 他們似乎都不適合我! 它給出第一個位置(甚至不正確的位置),然后中斷,第二個和第三個不執行任何操作...
任何人都可以看到錯誤嗎? 或者甚至更好地知道或可以編寫代碼以獲取所需的功能?
lat1,lon1-當前點!
我在不大的區域有300個標記,因此腳本不難找到3個最近的標記。
如果您遍歷標記,則可以在每個標記上調用此方法,然后將結果存儲在可以對數組進行排序的數組中。 這將是一項昂貴的操作...
/**
* This will give you the distance in kilometers between 2 positions
*
* @param lat1 - The first positions latitude
* @param lng2 - The first positions longitude
* @param lat2 - The second positions latitide
* @param lng2 - The second positions longitude
*
* @return int- The distance in kilometers between the 2 places
*/
distanceFrom : function(lat1,lng1, lat2, lng2) {
var R = 6371; // km
var dLat = this._toRad((lat2-lat1));
var dLon = this._toRad((lng2-lng1));
var lat1 = this._toRad(lat1);
var lat2 = this._toRad(lat2);
var a = Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.sin(dLon/2) * Math.sin(dLon/2) * Math.cos(lat1) * Math.cos(lat2);
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c;
return d;
}
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