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如何從我的應用程序中選擇Android手機的聯系電話?

[英]How to pick contact number from phone-book of android in to my application?

所有我想從我的應用程序數據庫中的android電話簿中獲取數字..我已經嘗試了下面的代碼,但這里得到的人的名字,而不是我想從電話簿號碼,並希望將其存儲在我的數據庫..如何實現這一目標可以任何人指導我..

@Override
    public void onActivityResult(int reqCode, int resultCode, Intent data){
        super.onActivityResult(reqCode, resultCode, data);

        switch(reqCode){
           case (PICK_CONTACT):
             if (resultCode == Activity.RESULT_OK){
                 Uri contactData = data.getData();
                 Cursor c = managedQuery(contactData, null, null, null, null);

                 if (c.moveToFirst()){
                     // other data is available for the Contact.  I have decided
                     //    to only get the name of the Contact.
                     String name = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.CONTENT_TYPE));
                     Toast.makeText(getApplicationContext(), name, Toast.LENGTH_SHORT).show();
                 }
             }
        }

提前致謝 -

我知道這是一個老問題,但我認為 Android下面的資源是在這個問題上非常有幫助。 “獎金”部分是raj正在尋找的確切代碼。 我認為這個鏈接應該對將來看到這個問題的人有所幫助,特別是如果你不了解CapDroid的片段。

http://developer.android.com/training/basics/intents/result.html

試試這段代碼,

  @Override public void onActivityResult(int reqCode, int resultCode, Intent data){ super.onActivityResult(reqCode, resultCode, data); switch(reqCode){ case (PICK_CONTACT): if (resultCode == Activity.RESULT_OK) { Uri contactData = data.getData(); Cursor c = managedQuery(contactData, null, null, null, null); if (c.moveToFirst()) { String id = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts._ID)); String hasPhone = c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); if (hasPhone.equalsIgnoreCase("1")) { Cursor phones = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id, null, null); phones.moveToFirst(); String cNumber = phones.getString(phones.getColumnIndex("data1")); } } } } 

這將有助於您:

public void onActivityResult(int reqCode, int resultCode, Intent data) { super.onActivityResult(reqCode, resultCode, data);

    try {
        if (resultCode == Activity.RESULT_OK) {
            Uri contactData = data.getData();
            Cursor cur = managedQuery(contactData, null, null, null, null);
            ContentResolver contect_resolver = getContentResolver();

            if (cur.moveToFirst()) {
                String id = cur.getString(cur.getColumnIndexOrThrow(ContactsContract.Contacts._ID));
                String name = "";
                String no = "";

                Cursor phoneCur = contect_resolver.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null,
                        ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", new String[]{id}, null);

                if (phoneCur.moveToFirst()) {
                    name = phoneCur.getString(phoneCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                    no = phoneCur.getString(phoneCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
                }

                Log.e("Phone no & name :***: ", name + " : " + no);
                txt.append(name + " : " + no + "\n");

                id = null;
                name = null;
                no = null;
                phoneCur = null;
            }
            contect_resolver = null;
            cur = null;
            //                      populateContacts();
        }
    } catch (IllegalArgumentException e) {
        e.printStackTrace();
        Log.e("IllegalArgumentException::", e.toString());
    } catch (Exception e) {
        e.printStackTrace();
        Log.e("Error :: ", e.toString());
    }
}

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