如何將數據返回到jquery ajax回調函數？

Question

如何將數據返回到jquery ajax回調函數，其中數據來自PHP mysql查詢。

<script language="javascript" type="text/javascript">
   $(document).ready(function() {
        $.post("getMySqlData", function(data){

        });
   });
</script>

這是執行mysql查詢以從mysql數據庫中選擇數據的PHP代碼

  <?php
    $host = "127.0.0.1";
    $user = "root";
    $password = "problem2";
    $database = "scsi_test_log";
    $cxn = mysqli_connect($host, $user, $password, $database) or die ("couldnt connect to server");

    $query = "SELECT test_header FROM scsi_test";
    $result = mysqli_query($cxn, $query) or die ("Couldn't execute query.");
  ?>

Answer 1

將結果提取到數組中，並以JSON編碼回顯 ;

$rows = array();
while ( $row = mysqli_fetch_assoc( $result ) ) {
    $rows[] = $row;
}

echo json_encode( $rows );