使用GSON解析json數據供稿

Question

我有一個簡單的JSON提要，它返回一個圖像路徑和一組協調。 “坐標”可以具有無限的一組坐標。 在下面的示例中，它只有3套。

{"image":"Some data", "coords": {"0":[0,0], "1":[55,22], "2":[46,65]}}

我將如何使用GSON解析此內容？ 我如何為此建立課程？

謝謝

Answer 1

您將很難，因為它不是有效的JSON。

http://jsonlint.com/

如果是有效的JSON，例如...

{"image":"Some data", "coords": {"0":[0,0], "1":[55,22], "2":[46,65]}}

我相信GSON可以將coords解析為<String, ArrayList<Integer>>的map ，但是我需要嘗試進行確認。

Answer 2

添加gson-1.7.1.jar文件並編寫此類，以從URL獲取所需的JSONObject或JSONArray 。

public class GetJson {

    public JSONArray readJsonArray(String url) {

        String read = null;
        JSONArray mJsonArray = null;
        try {
            HttpClient http = new DefaultHttpClient();
            HttpPost post = new HttpPost(url);
            HttpResponse response = http.execute(post);
            HttpEntity entity = response.getEntity();
            InputStream is = entity.getContent();

            BufferedReader br = new BufferedReader(new InputStreamReader(is));
            StringBuilder builder = new StringBuilder();
            String str = null;
            while ((str = br.readLine()) != null) {
                builder.append(str);
            }
            is.close();
            read = builder.toString();
            mJsonArray = new JSONArray(read);
        } catch (Exception e) {
            e.printStackTrace();
        }
        return mJsonArray;
    }

    public JSONObject readJsonObject(String url) {
        String read = null;
        JSONObject mJsonObject = null;
        try {
            HttpClient http = new DefaultHttpClient();
            HttpPost post = new HttpPost(url);
            HttpResponse response = http.execute(post);
            HttpEntity entity = response.getEntity();
            InputStream is = entity.getContent();

            BufferedReader br = new BufferedReader(new InputStreamReader(is));
            StringBuilder builder = new StringBuilder();
            String str = null;
            while ((str = br.readLine()) != null) {
                builder.append(str);
            }
            is.close();
            read = builder.toString();
            mJsonObject = new JSONObject(read);
        } catch (Exception e) {
            e.printStackTrace();
        }
        return mJsonObject;
    }
}

請享用...

然后要解析JSON，請參閱以下教程，

教程1

教程2

教程3